Nursing Elites

1. What describes a criterion used to diagnose diabetes?

• A. a plasma glucose concentration of 100 mg/dL or higher after a fast of at least 12 hours
• B. a casual blood sample of 200 mg/dL or higher in a person with classic symptoms
• C. a plasma glucose concentration measured two hours after a 200-gram glucose load is 400 mg/dL or higher
• D. a HbA1C higher than 5 percent

Correct answer: B

Rationale: A casual blood sample of 200 mg/dL or higher in a person with classic symptoms is a diagnostic criterion for diabetes. This choice aligns with the typical clinical presentation of diabetes and is a key diagnostic indicator. Choices A, C, and D do not accurately reflect the established criteria for diagnosing diabetes, making them incorrect. Choice A pertains to a fasting plasma glucose level, Choice C involves a glucose challenge test, and Choice D refers to HbA1C levels, which are used for monitoring blood sugar control over time, not for diagnosing diabetes.

2. Induction of vomiting is indicated for the accidental poisoning patient who has ingested.

• A. Rust remover C. toilet bowl cleaner
• B. Gasoline D. aspirin
• C.
• D.

Correct answer: D

Rationale: Understanding the underlying pathology and therapeutic techniques ensures that nursing care is not only reactive but also preventative, reducing the risk of complications.

3. Which type of immunity is demonstrated by the transfer of a mother's immunoglobulin across the placenta to protect the child?

• A. Natural active immunity
• B. Natural passive immunity
• C. Artificial active immunity
• D. Artificial passive immunity

Correct answer: B

Rationale: The immunoglobulin passed from the mother to the child through the placenta is an example of natural passive immunity, making choice B the correct answer. This transfer gives the child temporary immunity to various diseases without their immune system having to work. On the other hand, natural active immunity (Choice A) occurs when the body produces its own antibodies in response to an antigen. Artificial active immunity (Choice C) is achieved through vaccinations, where the immune system is stimulated to produce antibodies against a specific disease. Artificial passive immunity (Choice D) is a temporary immunity that involves the transfer of pre-formed antibodies from another source.

4. One of the most common factors that compromise the vitamin D status of older adults, particularly those living in assisted living communities is _____.

• A. decreased intake of fruits and vegetables
• B. lack of physical activity
• C. malabsorption due to atrophic gastritis
• D. lack of exposure to sunlight

Correct answer: D

Rationale: The correct answer is 'D: lack of exposure to sunlight.' Older adults, especially those in assisted living communities, are at risk of vitamin D deficiency due to spending most of their time indoors, which reduces their exposure to sunlight. Sunlight is essential for the body to produce vitamin D. Choices A, B, and C are less likely to be major factors in compromising vitamin D status. While a decreased intake of fruits and vegetables and lack of physical activity can impact overall health, they are not as directly related to vitamin D status. Malabsorption due to atrophic gastritis may affect the absorption of certain nutrients, but vitamin D synthesis primarily depends on sunlight exposure.

5. Which type of medication is most likely to induce xerostomia?

• A. Antibiotics
• B. Diuretics
• C. Local anesthetics
• D. Anticholinergics

Correct answer: D

Rationale: The correct answer is D, Anticholinergics. Anticholinergic medications commonly cause xerostomia by inhibiting saliva production, leading to dry mouth. Antibiotics (choice A) are not typically associated with xerostomia. Diuretics (choice B) increase urine production but do not directly affect saliva production. Local anesthetics (choice C) are used to numb specific areas during dental procedures and do not induce xerostomia.

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