Nursing Elites

1. A patient is being treated with raloxifene (Evista) for osteoporosis. What should the nurse teach the patient about this medication?

• A. It is used as a selective estrogen receptor modulator to prevent bone loss.
• B. It works by decreasing bone formation and increasing bone resorption.
• C. It should be taken with food to reduce gastrointestinal side effects.
• D. It may cause weight gain and fluid retention.

Correct answer: C

Rationale: The correct answer is C. Raloxifene is a selective estrogen receptor modulator (SERM) used to prevent bone loss. It should be taken with food to reduce gastrointestinal side effects, not on an empty stomach. Choices A and B are incorrect because raloxifene is indeed a SERM that prevents bone loss, but it does not directly work by increasing bone formation or decreasing bone resorption. Choice D is incorrect as weight gain and fluid retention are not common side effects of raloxifene.

2. A homeless man was screened for tuberculosis (TB) during a health consultation at a shelter, and the results indicate latent TB. The community health nurse who is liaising with the providers of the shelter would anticipate what component of this man's plan of care?

• A. The man will undergo conservative treatment for TB using adjuvant medications.
• B. The man will be treated for TB using first-line antitubercular drugs.
• C. The man will be monitored closely to determine if treatment is necessary.
• D. The man will be screened again in 10 to 12 weeks to determine if he has developed active TB.

Correct answer: B

Rationale: The correct answer is B. When a patient is diagnosed with latent TB infection, the standard approach involves treating them with first-line antitubercular drugs to prevent the progression to active TB. Adjuvant medications are not typically used for latent TB. Close monitoring without initiating treatment can lead to the development of active TB, so immediate treatment is crucial. Screening the individual again in 10 to 12 weeks does not address the immediate need for treatment of latent TB, which is essential to prevent the progression of the disease.

3. Canola oil produced from genetically modified canola plants altered to be herbicide-resistant is an example of a:

• A. pesticide-free food.
• B. saturated fat food.
• C. genetically modified food.
• D. product that is pure.

Correct answer: C

Rationale: The correct answer is 'genetically modified food.' Canola oil derived from genetically modified canola plants falls into this category because the plant's genome has been altered to exhibit herbicide resistance. This genetic modification makes it a genetically modified food. Choice A, 'pesticide-free food,' is incorrect as the genetic modification is to resist herbicides, not pesticides. Choice B, 'saturated fat food,' is incorrect as it does not accurately describe the genetic modification of the canola plants. Choice D, 'product that is pure,' is too vague and does not address the genetic modification aspect of the canola plants.

4. What lab results would be noted in a client with leukocytosis?

• A. Increased white blood cell count
• B. Increased platelet count
• C. Decreased white blood cell count
• D. Decreased platelet count

Correct answer: A

Rationale: Leukocytosis is a condition characterized by an elevated white blood cell count, typically in response to infection or inflammation. Therefore, the correct answer is an increased white blood cell count (Choice A). Increased platelet count (Choice B) is not a typical finding in leukocytosis. Choices C and D, decreased white blood cell count and decreased platelet count respectively, are opposite to what would be expected in leukocytosis and are therefore incorrect.

5. Which of the following are normal arterial blood gas values?

• A. PH 7.25, PaCO2 52 mm Hg, PaO2 75 mm Hg, HCO3 18 mEq/L
• B. PH 7.50, PaCO2 30 mm Hg, PaO2 80 mm Hg, HCO3 28 mEq/L
• C. PH 7.40, PaCO2 40 mm Hg, PaO2 90 mm Hg, HCO3 24 mEq/L
• D. PH 7.15, PaCO2 30 mm Hg, PaO2 50 mm Hg, HCO3 24 mEq/L

Correct answer: C

Rationale: The correct answer is C: PH 7.40, PaCO2 40 mm Hg, PaO2 90 mm Hg, HCO3 24 mEq/L. These values represent a balanced state for arterial blood gas. Choice A has lower than normal PH and HCO3 levels and higher PaCO2 and lower PaO2 levels. Choice B has higher than normal PH and HCO3 levels, lower PaCO2, and a normal PaO2 level. Choice D has a significantly lower PH and PaO2 level, normal HCO3 level, and low PaCO2 level, indicating an acidic state with impaired oxygenation.

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