Nursing Elites

1. What is the first-line treatment for a patient experiencing wheezing and coughing due to an allergic reaction?

• A. Albuterol via nebulizer
• B. Methylprednisolone 100 mg IV
• C. Cromolyn 20 mg via nebulizer
• D. Aminophylline 500 mg IV

Correct answer: A

Rationale: The correct answer is A: Albuterol via nebulizer. Albuterol is the first-line treatment for wheezing caused by an allergic reaction as it quickly opens the airways, providing rapid relief. Choice B, Methylprednisolone 100 mg IV, is a systemic corticosteroid that may be used in severe cases to reduce inflammation but is not the initial treatment for acute wheezing. Choice C, Cromolyn 20 mg via nebulizer, is a mast cell stabilizer that is more commonly used for prophylaxis rather than acute relief in allergic conditions. Choice D, Aminophylline 500 mg IV, is a bronchodilator that is less commonly used now due to its narrow therapeutic window and potential for toxicity, making it less preferred than Albuterol for initial treatment of wheezing.

2. What is an escharotomy and why is it performed?

• A. A surgical incision made to improve circulation in burn injuries
• B. A procedure to remove dead tissue from a wound
• C. A procedure to remove excess fluid from the lungs
• D. A procedure to relieve pain from burns

Correct answer: A

Rationale: An escharotomy is a surgical procedure involving an incision through the eschar (dead tissue) to relieve pressure in burn injuries. It is performed to improve circulation to the affected area, prevent further damage, and restore blood flow. Choice B is incorrect because an escharotomy is not primarily focused on removing dead tissue but rather on relieving pressure. Choice C is incorrect as it describes a procedure related to pulmonary issues, not burn injuries. Choice D is incorrect because while pain relief may be a result of an escharotomy, it is not the primary purpose of the procedure.

3. What are the priority lab values to monitor in a patient with HIV?

• A. CD4 T-cell count below 180 cells/mm3
• B. White blood cell count
• C. Hemoglobin levels
• D. Serum albumin levels

Correct answer: A

Rationale: The correct answer is A: CD4 T-cell count below 180 cells/mm3. Monitoring the CD4 T-cell count is crucial in patients with HIV as it indicates the level of immunocompromise. A CD4 count below 180 cells/mm3 is considered severe immunocompromise and requires close monitoring and intervention. Choices B, C, and D are not the priority lab values to monitor in HIV patients. While white blood cell count, hemoglobin levels, and serum albumin levels can provide valuable information about the patient's health status, they are not as specific or indicative of HIV disease progression and management as the CD4 T-cell count.

4. A nurse is assessing a client who has meningitis. The nurse should identify which of the following findings as a positive Kernig's sign?

• A. After stroking the lateral area of the foot, the client's toes contract and draw together
• B. After hip flexion, the client is unable to extend their leg completely without pain
• C. The client's voluntary movement is not coordinated
• D. The client reports pain and stiffness when flexing their neck

Correct answer: B

Rationale: A positive Kernig's sign is identified when a client is unable to extend their leg completely without pain after hip flexion. This finding suggests meningeal irritation. Choices A, C, and D do not describe Kernig's sign. Choice A describes a normal plantar reflex, Choice C refers to coordination deficits, and Choice D indicates neck pain and stiffness, which are not related to Kernig's sign.

5. What are the expected findings in a patient experiencing hypokalemia?

• A. Flattened T waves on an ECG
• B. Elevated ST segments
• C. Prominent U waves
• D. Bradycardia

Correct answer: A

Rationale: The correct answer is A: Flattened T waves on an ECG. Hypokalemia is characterized by flattened T waves on an ECG, which is an early indicator of low potassium levels. Elevated ST segments (Choice B) are associated with conditions like myocardial infarction, not hypokalemia. Prominent U waves (Choice C) are typically seen in hypokalemia, but flattened T waves are more specific. Bradycardia (Choice D) can be a manifestation of severe hypokalemia but is not as specific as flattened T waves on an ECG.

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