Nursing Elites

1. What is an escharotomy and why is it performed?

• A. A surgical incision made to improve circulation in burn injuries
• B. A procedure to remove dead tissue from a wound
• C. A procedure to remove excess fluid from the lungs
• D. A procedure to relieve pain from burns

Correct answer: A

Rationale: An escharotomy is a surgical procedure involving an incision through the eschar (dead tissue) to relieve pressure in burn injuries. It is performed to improve circulation to the affected area, prevent further damage, and restore blood flow. Choice B is incorrect because an escharotomy is not primarily focused on removing dead tissue but rather on relieving pressure. Choice C is incorrect as it describes a procedure related to pulmonary issues, not burn injuries. Choice D is incorrect because while pain relief may be a result of an escharotomy, it is not the primary purpose of the procedure.

2. A nurse is caring for a client who has a new diagnosis of tuberculosis. Which of the following precautions should the nurse initiate to prevent transmission of the disease?

• A. Contact precautions
• B. Airborne precautions
• C. Droplet precautions
• D. Protective environment

Correct answer: B

Rationale: Tuberculosis is spread through small droplets measuring less than 5 microns, which can remain airborne for extended periods. The nurse should place a client who has TB under airborne precautions to prevent the spread of microbes. Choice A, contact precautions, are used for diseases spread by direct or indirect contact. Choice C, droplet precautions, are for diseases spread by larger droplets. Choice D, protective environment, is used for immunocompromised clients to protect them from environmental pathogens.

3. What are the early signs of hypokalemia on an ECG?

• A. Flattened T waves
• B. Elevated ST segments
• C. Prominent U waves
• D. Widened QRS complex

Correct answer: A

Rationale: Flattened T waves are an early sign of hypokalemia on an ECG. In hypokalemia, the T waves may flatten and eventually invert. Elevated ST segments are not typically associated with hypokalemia. Prominent U waves are seen in conditions like hypokalemia, but they are not considered an early sign. A widened QRS complex is more commonly associated with hyperkalemia rather than hypokalemia.

4. What is the first medication to give to a patient with wheezing due to an allergic reaction?

• A. Albuterol via nebulizer
• B. Methylprednisolone 100 mg IV
• C. Cromolyn 20 mg via nebulizer
• D. Aminophylline 500 mg IV

Correct answer: A

Rationale: The correct answer is A, Albuterol via nebulizer. Albuterol is the first-line treatment for wheezing caused by an allergic reaction because it is a fast-acting bronchodilator that helps to quickly open the airways, providing immediate relief of symptoms. Choice B, Methylprednisolone 100 mg IV, is a corticosteroid used for its anti-inflammatory effects but is not the initial medication for acute wheezing in an allergic reaction. Choice C, Cromolyn 20 mg via nebulizer, is a mast cell stabilizer that can be used for prevention but is not the first choice for acute symptom relief. Choice D, Aminophylline 500 mg IV, is a bronchodilator with a narrow therapeutic window and more side effects compared to Albuterol, making it a less preferred option as the initial treatment.

5. What ECG change is associated with hyperkalemia?

• A. Flattened T waves
• B. ST depression
• C. Prominent U waves
• D. Elevated ST segments

Correct answer: B

Rationale: The correct ECG change associated with hyperkalemia is ST depression. Hyperkalemia typically presents with ECG changes such as peaked T waves, prolonged PR interval, widened QRS complex, and finally, ST segment depression. Flattened T waves are more commonly associated with hypokalemia. Prominent U waves are seen in hypokalemia as well. Elevated ST segments are not a typical ECG finding in hyperkalemia.

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