Nursing Elites

1. Third spacing occurs when fluid moves out of the intravascular space but not into the intracellular space. Based on this fluid shift, the nurse will expect the patient to demonstrate:

• A. Hypertension
• B. Bradycardia
• C. Hypervolemia
• D. Hypovolemia

Correct answer: D

Rationale: In the scenario of third-spacing fluid shift, where fluid moves out of the intravascular space but not into the intracellular space, the patient is expected to demonstrate hypovolemia. Hypertension (Choice A) is unlikely as hypovolemia typically leads to decreased blood pressure. Bradycardia (Choice B) is not a common manifestation of hypovolemia, as the body often tries to compensate by increasing heart rate. Hypervolemia (Choice C) indicates an excess of fluid, which is the opposite of what occurs in third spacing.

2. A patient with a longstanding diagnosis of generalized anxiety disorder presents to the emergency room. The triage nurse notes upon assessment that the patient is hyperventilating. The triage nurse is aware that hyperventilation is the most common cause

• A. Respiratory acidosis
• B. Respiratory alkalosis
• C. Increased PaCO2
• D. CNS disturbances

Correct answer: B

Rationale:

3. Which of the following statements is correct?

• A. People with less body fat have more body water.
• B. Infants have more water per pound than adults.
• C. Females have more body water per pound than males.
• D. Infants have the same water content per pound as adults.

Correct answer: A

Rationale: The correct statement is that people with less body fat have more body water. This is because fat tissue contains less water compared to lean tissue, so individuals with less body fat generally have a higher percentage of body water. Choice B is incorrect as infants actually have more water per pound than adults due to their higher body water content. Choice C is incorrect as males typically have more body water per pound than females. Choice D is incorrect as infants have a higher water content per pound compared to adults.

4. Your patient has the following arterial blood gas results: pH 7.26, PaCO2 28, HCO3 11 mEq/L. How would the nurse interpret the results?

• A. Respiratory acidosis with no compensation
• B. Metabolic alkalosis with a compensatory alkalosis
• C. Metabolic acidosis with no compensation
• D. Metabolic acidosis with a compensatory respiratory alkalosis

Correct answer: D

Rationale: The given arterial blood gas results show a low pH, indicating acidosis, with normal pH range being 7.35 to 7.45. The low PaCO2 suggests alkalosis, while the low bicarb level indicates acidosis. In this scenario, the primary issue is the metabolic acidosis, as the pH bicarb relationship supports this. The compensatory response to metabolic acidosis is a decrease in PaCO2, leading to a respiratory alkalosis. Therefore, the correct interpretation is 'Metabolic acidosis with a compensatory respiratory alkalosis.' Choices A, B, and C are incorrect as they do not accurately reflect the relationship between the pH, PaCO2, and HCO3 levels in the arterial blood gas results provided.

5. A patient is taking spironolactone (Aldactone) to control her hypertension. Her serum potassium level is 6 mEq/L. For this patient, the nurse's priority would be to assess her:

• A. Neuromuscular function
• B. Bowel sounds
• C. Respiratory rate
• D. Electrocardiogram (ECG) results

Correct answer: D

Rationale: In a patient with a serum potassium level of 6 mEq/L due to spironolactone use, the nurse's priority is to assess the Electrocardiogram (ECG) results. Hyperkalemia can lead to life-threatening arrhythmias, such as ventricular fibrillation, which can be detected on an ECG. While changes in neuromuscular function, bowel sounds, and respiratory rate can occur with hyperkalemia, the most critical assessment related to the patient's condition would be monitoring the ECG for signs of cardiac complications.

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