Nursing Elites

1. The nurse is assessing the perineal wound in a client who has returned from the operating room following an abdominal perineal resection and notes serosanguineous drainage from the wound. Which nursing intervention is most appropriate?

• A. Clamp the Penrose drain.
• B. Change the dressing as prescribed.
• C. Notify the healthcare provider (HCP).
• D. Remove and replace the perineal packing.

Correct answer: B

Rationale: In this scenario, the appropriate nursing intervention for serosanguineous drainage from the wound is to change the dressing as prescribed. This helps in maintaining wound cleanliness, preventing infection, and promoting proper wound healing. Clamping the Penrose drain (Choice A) is not indicated as the drainage is from the wound itself, not the drain. Notifying the healthcare provider (Choice C) may be necessary if there are signs of infection or other concerning issues, but changing the dressing should be done first. Removing and replacing the perineal packing (Choice D) is not the priority in this situation unless specifically prescribed by the healthcare provider after assessing the wound.

2. A client with cancer has anorexia and mucositis, and is losing weight. The client’s family members continually bring favorite foods to the client and are distressed when the client won’t eat them. What action by the nurse is best?

• A. Explain the pathophysiologic reasons behind the client not eating.
• B. Help the family show other ways to demonstrate love and caring.
• C. Suggest foods and liquids the client might be willing to try to eat.
• D. Tell the family the client isn’t able to eat now no matter what they bring.

Correct answer: B

Rationale: The best action for the nurse in this situation is to help the family show other ways to demonstrate love and caring. When a client with cancer is experiencing anorexia and mucositis, it can be challenging for them to eat even their favorite foods. By assisting the family in finding alternative ways to provide comfort and care, the nurse can help create a supportive environment for the client. Option A is not the best choice as explaining the pathophysiologic reasons may not address the emotional needs of the client and family. Option C, suggesting foods and liquids, might not be helpful if the client is unable to tolerate them due to their condition. Option D, telling the family that the client can't eat, may come across as dismissive and not supportive of the family's concerns.

3. Nurse Mike is providing care to a client with chronic myelogenous leukemia (CML). The nurse knows that the client is at risk for tumor lysis syndrome. Which of the following laboratory values requires immediate intervention?

• A. Increased uric acid level
• B. Increased serum potassium level
• C. Increased serum sodium level
• D. Increased fibrinogen level

Correct answer: A

Rationale: The correct answer is A: Increased uric acid level. In tumor lysis syndrome, rapid cell destruction releases large amounts of potassium, phosphate, and nucleic acids into the bloodstream. Uric acid can accumulate rapidly, leading to hyperuricemia, which can result in kidney damage due to urate crystal deposition. Immediate intervention is necessary to prevent renal complications. Choices B, C, and D are incorrect because while electrolyte imbalances are common in tumor lysis syndrome, hyperuricemia with potential kidney damage is the priority concern that requires immediate attention.

4. During the admission assessment of a client with advanced ovarian cancer, the nurse recognizes which symptom as typical of the disease?

• A. Diarrhea
• B. Hypermenorrhea
• C. Abnormal bleeding
• D. Abdominal distention

Correct answer: D

Rationale: Abdominal distention is a common symptom in advanced ovarian cancer due to several factors, including the accumulation of ascites (fluid in the abdominal cavity) and the presence of tumors that can increase abdominal girth. As the disease progresses, the pressure from growing masses or fluid buildup can lead to noticeable swelling and discomfort in the abdomen. This symptom often prompts further evaluation and can significantly impact the patient’s quality of life.

5. The cells of a normal individual can replicate in a specified rate. If the rate of replication becomes uncontrollable, which of the following is lacking from the patient?

• A. Apoptosis
• B. Contact inhibition
• C. Stable cells
• D. Labile cells

Correct answer: B

Rationale: Contact inhibition is a regulatory mechanism that prevents cells from proliferating once they reach a certain density. Normally, when cells grow and touch each other (such as in a monolayer), they stop dividing, maintaining tissue integrity and structure. When contact inhibition is lacking, as in many cancerous cells, cells continue to grow and divide uncontrollably, leading to tumor formation. This loss of regulation is a hallmark of cancerous growth.

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