ATI RN
ATI Medical Surgical Proctored Exam 2023
1. A client with chronic obstructive pulmonary disease (COPD) is being taught by a nurse. What nutrition information should the nurse include in the teaching?
- A. Avoid drinking fluids just before and during meals.
- B. Rest before meals if experiencing dyspnea.
- C. Consume about six small meals a day.
- D. Consume high-fiber foods to promote gastric emptying.
Correct answer: D
Rationale: While some of the other options may be helpful, the most appropriate advice for a client with COPD is to consume high-fiber foods to promote gastric emptying. Avoiding fluids just before and during meals can help prevent bloating, resting before meals can assist with dyspnea, and having several small meals a day can help reduce bloating. However, fibrous foods can lead to gas production, causing abdominal bloating and potentially worsening shortness of breath. Increasing calorie and protein intake is essential to prevent malnourishment. It is also important to avoid excessive carbohydrate intake, as it can increase carbon dioxide production and the risk of acidosis in COPD patients.
2. A nurse in an urgent care center is caring for a client who is having an acute asthma exacerbation. Which of the following actions is the nurse's highest priority?
- A. Initiating oxygen therapy
- B. Providing immediate rest for the client
- C. Positioning the client in high-Fowler's
- D. Administering a nebulized beta-adrenergic
Correct answer: D
Rationale: During an acute asthma exacerbation, the priority intervention is to administer a nebulized beta-adrenergic medication, such as albuterol, to help open the airways and improve breathing. This action helps address the underlying cause of the exacerbation. Oxygen therapy may be needed but is not the priority over administering the bronchodilator. Providing rest and positioning the client in high-Fowler's are important but come after administering the medication to address the immediate breathing difficulties.
3. A client is hospitalized with a second episode of pulmonary embolism (PE). Recent genetic testing reveals the client has an alteration in the gene CYP2C19. What action by the nurse is best?
- A. Instruct the client to eliminate all vitamin K from the diet.
- B. Prepare preoperative teaching for an inferior vena cava (IVC) filter.
- C. Refer the client to a chronic illness support group.
- D. Teach the client to use a soft-bristled toothbrush.
Correct answer: B
Rationale: Clients with an alteration in the CYP2C19 gene do not metabolize warfarin (Coumadin) well, leading to higher blood levels and more side effects. As this client is a poor candidate for warfarin therapy, the prescriber will most likely recommend the implantation of an inferior vena cava (IVC) filter. This device helps prevent blood clots from reaching the lungs, reducing the risk of pulmonary embolism.
4. A student learns about modifiable risk factors for coronary artery disease. Which factors does this include? (Select one that does not apply)
- A. Age
- B. Hypertension
- C. Obesity
- D. Smoking
Correct answer: A
Rationale: Hypertension, obesity, smoking, and excessive stress are all modifiable risk factors for coronary artery disease, as they can be changed or controlled through interventions. Age, on the other hand, is a nonmodifiable risk factor, meaning it cannot be altered. Understanding the difference between modifiable and nonmodifiable risk factors is essential in preventive healthcare strategies.
5. A healthcare professional is preparing to administer albuterol syrup 1.6 mg PO tid. Available is albuterol 2 mg/5mL. How many mL should the healthcare professional administer per dose? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
- A. 4 mL
- B. 6 mL
- C. 10 mL
- D. 5.5 mL
Correct answer: A
Rationale: To calculate the mL of albuterol syrup needed per dose, first, determine how many milligrams are in the prescribed dose: 1.6 mg. Next, set up a proportion to find the equivalent mL for 1.6 mg using the given concentration of 2 mg/5mL. The calculation is: (1.6 mg x 5 mL) / 2 mg = 4 mL. Therefore, the correct answer is 4 mL to administer per dose.
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