ATI RN
ATI Medical Surgical Proctored Exam
1. After auscultating a client's breath sounds, the nurse is providing care. Which finding is correctly matched to the nurse's primary intervention?
- A. Hollow sounds are heard over the trachea. The nurse increases the oxygen flow rate.
- B. Crackles are heard in bases. The nurse encourages the client to cough forcefully.
- C. Wheezes are heard in central areas. The nurse administers an inhaled bronchodilator.
- D. Vesicular sounds are heard over the periphery. The nurse has the client breathe deeply.
Correct answer: C
Rationale: Wheezes are indicative of narrowed airways, and bronchodilators help to open the air passages, making option C the correct match. Wheezes are typically heard in the central or peripheral lung areas and are associated with conditions like asthma or COPD. Inhaled bronchodilators work by dilating the bronchioles, which helps alleviate wheezing and improve airflow. Therefore, administering an inhaled bronchodilator is the appropriate intervention in response to wheezes.
2. When admitting a client with active tuberculosis to a room on a medical-surgical unit, which of the following room assignments should the nurse make?
- A. A room with air exhaust directly to the outdoor environment
- B. A room with another nonsurgical client
- C. A room in the ICU
- D. A room that is within view of the nurses' station
Correct answer: A
Rationale: When admitting a client with active tuberculosis, it is crucial to assign them to a room with air exhaust directly to the outdoor environment to prevent the spread of infectious particles to other patients and healthcare workers. This setup helps in reducing the risk of transmission within the healthcare facility. Placing the client in a room with another nonsurgical client or in the ICU may increase the chances of spreading the infection. Additionally, placing the client in a room within view of the nurses' station does not address the need for proper ventilation to minimize transmission of tuberculosis.
3. A client who is receiving mechanical ventilation and has an ideal weight of 60 kg should have the tidal volume set at which of the following?
- A. 300 mL
- B. 480 mL
- C. 800 mL
- D. 950 mL
Correct answer: B
Rationale: Tidal volume is the amount of air delivered with each breath during mechanical ventilation. A common formula used to calculate tidal volume is 6-8 mL/kg of ideal body weight. For a client with an ideal weight of 60 kg, the expected tidal volume would be 60 kg x 6-8 mL/kg = 360-480 mL. Therefore, the most appropriate choice is 480 mL (Option B), which falls within the expected range based on the client's weight.
4. A healthcare professional is assessing a client with left-sided heart failure. Which finding is most commonly associated with this condition?
- A. Peripheral edema
- B. Jugular vein distention
- C. Hepatomegaly
- D. Crackles in the lungs
Correct answer: D
Rationale: Crackles in the lungs are commonly associated with left-sided heart failure due to pulmonary congestion. Left-sided heart failure leads to the backup of blood into the lungs, causing fluid leakage into the alveoli, which results in the characteristic crackling sound upon auscultation.
5. A nurse is caring for a client post-myocardial infarction (MI). What is the priority assessment for this client?
- A. Monitoring urine output
- B. Checking blood glucose levels
- C. Assessing for chest pain
- D. Monitoring electrolyte levels
Correct answer: C
Rationale: Assessing for chest pain is crucial in post-MI clients as it can indicate complications such as reinfarction or ischemia.
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