the immunoglobulin of the mother that crosses the placenta to protect the child is an example of
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Nursing Elites

ATI RN

ATI Nutrition Practice Test A 2019

1. Which type of immunity is demonstrated by the transfer of a mother's immunoglobulin across the placenta to protect the child?

Correct answer: B

Rationale: The immunoglobulin passed from the mother to the child through the placenta is an example of natural passive immunity, making choice B the correct answer. This transfer gives the child temporary immunity to various diseases without their immune system having to work. On the other hand, natural active immunity (Choice A) occurs when the body produces its own antibodies in response to an antigen. Artificial active immunity (Choice C) is achieved through vaccinations, where the immune system is stimulated to produce antibodies against a specific disease. Artificial passive immunity (Choice D) is a temporary immunity that involves the transfer of pre-formed antibodies from another source.

2. Which food is the best source of omega-3 fatty acids?

Correct answer: B

Rationale: Salmon is high in omega-3 fatty acids, beneficial for cardiovascular health.

3. A client is prescribed a 1500-calorie diet. Thirty percent of the calories are to be derived from fat. How many grams of fat should the nurse tell the client to consume per day? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)

Correct answer: D

Rationale: To calculate the grams of fat, first, determine the calories from fat by multiplying the total calorie intake (1500 calories) by the percentage of calories from fat (30%), which equals 450 calories from fat. Since 1 gram of fat is equivalent to 9 calories, divide the total calories from fat (450) by the calories in 1 gram of fat (9) to get the answer in grams, which is 50. Therefore, the client should consume 50 grams of fat per day. Choice A (21), Choice B (49), and Choice C (60) are incorrect as they do not reflect the accurate calculation based on the given information.

4. Which is most likely to initiate periodontal disease?

Correct answer: D

Rationale: Plaque biofilm is the primary initiator of periodontal disease, as it harbors bacteria that can lead to inflammation and destruction of the periodontal tissues.

5. Cariogenic foods and beverages, which are fermentable carbohydrates that can be metabolized by oral bacteria, reduce salivary pH to what critical level?

Correct answer: B

Rationale: Cariogenic foods and beverages lower the pH level in the mouth to below 5.5. This is a critical threshold, as it is the point at which enamel begins to demineralize, increasing the risk of dental caries. Therefore, options 'A', 'C', and 'D' are incorrect. Although a pH level of 5, as suggested by option 'A', would indeed lead to demineralization, it's not the threshold value. The pH levels suggested by options 'C' and 'D' (6 and 6.5, respectively) are higher than the critical value of 5.5, which means they would not initiate enamel demineralization and the subsequent risk of dental caries.

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