ATI RN
Pathophysiology Practice Exam
1. A patient with a history of venous thromboembolism is being considered for hormone replacement therapy (HRT). What should the nurse discuss with the patient regarding the risks of HRT?
- A. Discuss the potential for increased bone density.
- B. Discuss the potential for an increased risk of cardiovascular events.
- C. Discuss the potential for a reduced risk of breast cancer.
- D. Discuss the potential for improved mood and energy levels.
Correct answer: B
Rationale: The correct answer is B because hormone replacement therapy (HRT) is associated with an increased risk of cardiovascular events, including venous thromboembolism. Patients with a history of venous thromboembolism are at higher risk, so discussing this potential risk is crucial. Choice A, increased bone density, is not a major risk of HRT. Choice C, reduced risk of breast cancer, is not a common discussion point regarding HRT risks. Choice D, improved mood and energy levels, is more related to the benefits of HRT rather than its risks.
2. A patient is taking raloxifene (Evista) for osteoporosis. What is the primary therapeutic effect of this medication?
- A. It stimulates the formation of new bone.
- B. It decreases bone resorption and increases bone density.
- C. It increases the excretion of calcium through the kidneys.
- D. It increases calcium absorption in the intestines.
Correct answer: B
Rationale: The correct answer is B. Raloxifene, a selective estrogen receptor modulator (SERM), primarily works by decreasing bone resorption and increasing bone density. This mechanism of action helps in the prevention and treatment of osteoporosis by maintaining or improving bone strength. Choice A is incorrect because raloxifene does not directly stimulate the formation of new bone but rather helps in preserving existing bone. Choice C is incorrect because raloxifene does not increase the excretion of calcium through the kidneys; instead, it acts on bone tissue. Choice D is incorrect as raloxifene does not directly increase calcium absorption in the intestines but rather focuses on bone health.
3. Which of the following is a characteristic of osteosarcoma?
- A. Slow-growing tumor that begins in the bone marrow
- B. Solitary tumor that most often affects the metaphyseal region of the femur or tibia
- C. An aggressive tumor most often found in the bone marrow of long bones
- D. A tumor that infiltrates the trabeculae in spongy bone and implants in surrounding tissue
Correct answer: C
Rationale: Osteosarcoma is an aggressive bone tumor that most commonly arises in the bone marrow of long bones, such as the femur or tibia. Choice A is incorrect as osteosarcoma is not a slow-growing tumor but rather a fast-growing one. Choice B is incorrect as osteosarcoma is not typically solitary but can involve multiple lesions. Choice D is incorrect as osteosarcoma primarily affects the medullary (marrow) cavity of bones, rather than infiltrating the trabeculae in spongy bone and surrounding tissue.
4. A patient has acute respiratory failure (ARF). Which of the following would the nurse expect to find?
- A. Alkalosis and hyperventilation
- B. Hypoxemia and hypercapnia
- C. Alkalosis and high potassium
- D. Elevated sodium and acidosis
Correct answer: B
Rationale: In acute respiratory failure, hypoxemia (low blood oxygen) and hypercapnia (high blood carbon dioxide) are commonly observed. Choice A is incorrect because alkalosis (high pH) and hyperventilation are not typically seen in acute respiratory failure. Choice C is incorrect as it mentions alkalosis and high potassium, which are not characteristic of acute respiratory failure. Choice D is also incorrect because elevated sodium and acidosis are not typically associated with acute respiratory failure.
5. A patient has been prescribed mifepristone (RU-486) to terminate a pregnancy. How does this drug achieve its therapeutic effect?
- A. By inhibiting the action of progesterone, which is necessary to maintain pregnancy.
- B. By increasing estrogen levels, which induce uterine contractions.
- C. By altering the uterine lining, preventing implantation.
- D. By stimulating uterine contractions, which expel the embryo.
Correct answer: A
Rationale: Mifepristone (RU-486) functions by inhibiting the action of progesterone, a hormone crucial for maintaining pregnancy. By blocking progesterone, mifepristone disrupts the uterine environment necessary for pregnancy continuation, ultimately leading to termination. Choice B is incorrect because mifepristone does not increase estrogen levels; instead, it acts on progesterone. Choice C is incorrect as mifepristone's mechanism does not involve altering the uterine lining to prevent implantation. Choice D is incorrect because mifepristone does not directly stimulate uterine contractions; its primary action is through progesterone inhibition.
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