Nursing Elites

1. A 20-year-old college student has presented to her campus medical clinic for a scheduled Pap smear. The clinician who will interpret the smear will examine cell samples for evidence of:

• A. Changes in cell shape, size, and organization
• B. Presence of unexpected cell types
• C. Ischemic changes in cell sample
• D. Abnormally high numbers of cells

Correct answer: A

Rationale: The correct answer is changes in cell shape, size, and organization (Choice A). Pap smears are performed to detect potential precancerous or cancerous conditions by examining the cells for any abnormalities in their shape, size, or organization. This helps in identifying early signs of cervical cancer. Choices B, C, and D are incorrect because Pap smears primarily focus on detecting cellular changes associated with cancer, not unexpected cell types, ischemic changes, or abnormally high numbers of cells.

2. A patient's anemia is described as having erythrocytes that demonstrate anisocytosis. The nurse would recognize the erythrocytes as:

• A. Pale in color
• B. Present in various sizes
• C. Able to assume various shapes
• D. Live only a few days

Correct answer: B

Rationale: The correct answer is B: 'Present in various sizes.' Anisocytosis refers to erythrocytes that are present in various sizes, indicating an abnormality in the uniformity of red blood cell size. Choice A is incorrect because anisocytosis does not refer to the color of erythrocytes. Choice C is incorrect as anisocytosis does not involve the shape of erythrocytes. Choice D is incorrect as anisocytosis does not determine the lifespan of erythrocytes.

3. When a healthcare professional notices that a patient has type O blood, they realize that anti-_____ antibodies are present in the patient's body.

• A. A only
• B. B only
• C. A and B
• D. O

Correct answer: C

Rationale: Individuals with type O blood have both anti-A and anti-B antibodies in their body. This is because type O blood lacks A or B antigens on the surface of red blood cells, causing the body to produce antibodies against both A and B antigens. Therefore, the correct answer is C. Choice A and B only antibodies are incorrect because type O individuals have both anti-A and anti-B antibodies. Choice D is incorrect as O represents the blood type itself, not the antibodies present in the blood.

4. In osteoporosis, what is the expected therapeutic action of raloxifene (Evista)?

• A. It decreases bone resorption and increases bone density.
• B. It stimulates the formation of new bone.
• C. It increases calcium absorption in the intestines.
• D. It decreases the excretion of calcium through the kidneys.

Correct answer: A

Rationale: The correct answer is A. Raloxifene works by decreasing bone resorption and increasing bone density. This helps in strengthening bones, reducing the risk of fractures, and improving bone health in patients with osteoporosis. Choice B is incorrect because raloxifene does not directly stimulate the formation of new bone but rather prevents bone loss. Choice C is incorrect as raloxifene does not primarily affect calcium absorption in the intestines. Choice D is also incorrect as raloxifene does not primarily decrease the excretion of calcium through the kidneys.

5. A patient has been diagnosed with cytomegalovirus (CMV). Which of the following drugs would be ineffective in the treatment of this disease?

• A. Ribavirin (Rebetol)
• B. Ganciclovir (Cytovene) IV
• C. Foscarnet (Foscavir) IV
• D. Valganciclovir hydrochloride (Valcyte)

Correct answer: A

Rationale: The correct answer is A, Ribavirin (Rebetol). Ribavirin is not effective against CMV. Choice B, Ganciclovir (Cytovene) IV, is a common treatment for CMV as it inhibits viral DNA synthesis. Choice C, Foscarnet (Foscavir) IV, is also used for CMV infections by blocking viral DNA polymerase. Choice D, Valganciclovir hydrochloride (Valcyte), is a prodrug of Ganciclovir and is effective against CMV. Therefore, Ribavirin is the drug that would be ineffective in treating CMV.

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