Nursing Elites

1. While giving care to a client with an internal cervical radiation implant, the nurse finds the implant in the bed. The nurse should take which initial action?

• A. Call the health care provider (HCP).
• B. Reinsert the implant into the vagina.
• C. Pick up the implant with gloved hands and flush it down the toilet.
• D. Pick up the implant with long-handled forceps and place it in a lead container.

Correct answer: D

Rationale: When caring for a client with an internal cervical radiation implant, safety measures must be followed to protect both the client and healthcare personnel from radiation exposure. If the implant becomes dislodged and is found in the bed, the nurse’s priority is to handle it safely using long-handled forceps, as direct contact with the implant could result in radiation exposure. The implant should be placed in a lead-lined container, which is specifically designed to shield against radiation, to prevent further contamination or exposure. After securing the implant, the nurse should notify the radiation safety officer or healthcare provider for further guidance.

2. A patient on the oncology unit is receiving carmustine, a chemotherapy agent, and the nurse is aware that a significant side effect of this medication is thrombocytopenia. Which symptom should the nurse assess for in patients at risk for thrombocytopenia?

• A. Interrupted sleep pattern
• B. Hot flashes
• C. Epistaxis (nose bleed)
• D. Increased weight

Correct answer: C

Rationale: Thrombocytopenia is a condition characterized by a low platelet count, which increases the risk of bleeding and hemorrhage. Patients receiving chemotherapy agents like carmustine may experience thrombocytopenia as a significant side effect. Epistaxis (nosebleeds) is a common symptom associated with thrombocytopenia, as the blood vessels can become more fragile, and even minor trauma or spontaneous bleeding can occur. Therefore, assessing for signs of bleeding, including epistaxis, is crucial in patients at risk for thrombocytopenia.

3. The cells of a normal individual can replicate in a specified rate. If the rate of replication becomes uncontrollable, which of the following is lacking from the patient?

• A. Apoptosis
• B. Contact inhibition
• C. Stable cells
• D. Labile cells

Correct answer: B

Rationale: Contact inhibition is a regulatory mechanism that prevents cells from proliferating once they reach a certain density. Normally, when cells grow and touch each other (such as in a monolayer), they stop dividing, maintaining tissue integrity and structure. When contact inhibition is lacking, as in many cancerous cells, cells continue to grow and divide uncontrollably, leading to tumor formation. This loss of regulation is a hallmark of cancerous growth.

4. A nurse is caring for a client with thrombocytopenia. Which action is the highest priority to reduce the risk of bleeding?

• A. Use an electric razor instead of a straight razor.
• B. Apply pressure to any bleeding sites for at least 5 minutes.
• C. Avoid invasive procedures unless absolutely necessary.
• D. Monitor for signs of internal bleeding.

Correct answer: C

Rationale: The highest priority action to reduce the risk of bleeding in a client with thrombocytopenia is to avoid invasive procedures unless absolutely necessary. Thrombocytopenia is a condition characterized by a low platelet count, which impairs the blood's ability to clot properly. By avoiding invasive procedures, the nurse minimizes the potential for bleeding episodes that could be challenging to control due to the low platelet count. Using an electric razor instead of a straight razor (Choice A) is a good practice to prevent cuts, but it is not as critical as avoiding invasive procedures in this scenario. Applying pressure to bleeding sites (Choice B) and monitoring for signs of internal bleeding (Choice D) are important interventions but are secondary to the priority of preventing bleeding by avoiding invasive procedures.

5. A nurse is planning the care of a patient who has been admitted to the medical unit with a diagnosis of multiple myeloma. In the patients care plan, the nurse has identified a diagnosis of Risk for Injury. What pathophysiologic effect of multiple myeloma most contributes to this risk?

• A. Labyrinthitis
• B. Left ventricular hypertrophy
• C. Decreased bone density
• D. Hypercoagulation

Correct answer: C

Rationale: In multiple myeloma, the malignant proliferation of plasma cells within the bone marrow leads to the secretion of osteoclast-activating factors, which increase the breakdown of bone tissue (osteolysis). This results in decreased bone density, osteoporosis, and osteolytic lesions, making bones fragile and more prone to pathologic fractures. Patients with multiple myeloma are at high risk for fractures even with minimal trauma due to the weakened bone structure, which is why Risk for Injury is a key diagnosis.

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