Nursing Elites

1. Clients with type 2 diabetes are most likely to achieve metabolic control if they:

• A. lose weight
• B. use self-monitoring of blood glucose
• C. eliminate all dietary sugars
• D. eat three regular meals daily

Correct answer: A

Rationale: Weight loss improves insulin sensitivity and glycemic control, making it a key strategy in managing type 2 diabetes.

2. What action should the nurse take first for a client with Listeria food poisoning?

• A. Educate the client on safe food practices.
• B. Start a traceback to identify the source of the outbreak.
• C. Report the case to the county board of health.
• D. Ask the client if they have consumed any unpasteurized products.

Correct answer: D

Rationale: Identifying the source of Listeria is crucial for preventing further cases.

3. Scurvy is caused by a deficiency of which vitamin?

• A. Vitamin A
• B. Vitamin D
• C. Vitamin E
• D. Vitamin K

Correct answer: C

Rationale: Scurvy is caused by a deficiency of vitamin C, not vitamin E. The symptoms of scurvy include spontaneous gingival hemorrhaging, perifollicular petechiae, follicular hyperkeratosis, diarrhea, fatigue, depression, and cessation of bone growth. Vitamin A (Choice A) is important for vision and immune function, Vitamin D (Choice B) is essential for bone health, and Vitamin K (Choice D) is necessary for blood clotting. However, none of these vitamins are associated with scurvy.

4. What is the initial major sign of acute renal failure?

• A. Oliguria
• B. Hematuria
• C. Proteinuria
• D. Glycosuria

Correct answer: A

Rationale: Oliguria, or reduced urine output, is often the initial major sign of acute renal failure. This reduction in urine output indicates that the kidneys are not functioning properly. Hematuria (blood in urine), proteinuria (presence of protein in urine), and glycosuria (presence of glucose in urine) are not typically the initial major signs of acute renal failure. While they may be present in certain conditions, oliguria is the most common and critical indicator of acute renal failure.

5. A nurse is reviewing blood glucose values for a client who is at risk for Diabetes Mellitus. Which of the following findings should the nurse report to the provider?

• A. 2-hour glucose tolerance test level 150 mg/dL
• B. Fasting blood glucose 70 mg/dL
• C. Glycosylated hemoglobin 5%
• D. Casual blood glucose 90 mg/dL

Correct answer: A

Rationale: The correct answer is A. A 2-hour glucose tolerance test level of 150 mg/dL is above the normal range and should be reported to the provider as it indicates impaired glucose tolerance. Choice B (Fasting blood glucose 70 mg/dL) is within the normal range. Choice C (Glycosylated hemoglobin 5%) is also within the normal range. Choice D (Casual blood glucose 90 mg/dL) is within the normal range and does not indicate impaired glucose tolerance.

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