Nursing Elites

1. After mitosis, the genetic code is identical in new cells unless _________ occur through radiation or other environmental influences.

• A. reductions
• B. expulsions
• C. conceptions
• D. mutations

Correct answer: D

Rationale: After mitosis, the genetic code is typically preserved and remains identical in the new cells. However, mutations can occur due to radiation or environmental influences, leading to changes in the DNA sequence and potentially altering the genetic code. Therefore, the correct answer is 'mutations.' Choices A, B, and C are incorrect because reductions, expulsions, and conceptions do not accurately describe the changes in the genetic code that can result from external factors. Mutations are the only option that reflects the alteration in the genetic code caused by external influences, making it the correct choice in this context.

2. The nurse has received a report regarding a client in labor. The woman’s last vaginal examination was recorded as 3 cm, 30%, and –2. What is the nurse’s interpretation of this assessment?

• A. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm above the ischial spines.
• B. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines.
• C. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm below the ischial spines.
• D. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm below the ischial spines.

Correct answer: B

Rationale: The correct interpretation of the assessment provided is that the cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines. In the given assessment, the measurements are ordered as dilation, effacement, and station. Choice A is incorrect as it wrongly places the presenting part below the ischial spines. Choice C is incorrect because it places the presenting part below the ischial spines. Choice D is also incorrect as it incorrectly states that the presenting part is below the ischial spines, even though it correctly mentions the dilation and effacement of the cervix.

3. A mother spontaneously delivers a newborn infant in the taxicab while on the way to the hospital. The emergency room nurse reported the mother has active herpes (HSV II) lesions on the vulva. Which intervention should the nurse implement first when admitting the neonate to the nursery?

• A. Document the newborn's temperature on the flow sheet.
• B. Place the newborn in the isolation area of the nursery.
• C. Obtain a blood specimen for a serum glucose level.
• D. Administer the vitamin K injection.

Correct answer: B

Rationale: Newborns exposed to active herpes lesions are at high risk for neonatal herpes, which can be severe. Placing the newborn in isolation is crucial as it helps prevent the spread of the virus and allows for close monitoring. Documenting the newborn's temperature, obtaining a blood specimen for a serum glucose level, and administering the vitamin K injection are important interventions but are not the priority when dealing with a potential infectious risk like neonatal herpes.

4. Rubella, also called German measles, is a viral infection passed from the mother to the fetus that can cause birth defects such as deafness, intellectual disabilities, blindness, and heart disease in the embryo.

• A. Rubella
• B. Syphilis
• C. Cystic fibrosis
• D. Phenylketonuria

Correct answer: A

Rationale: Rubella, also known as German measles, is a viral infection that can lead to severe birth defects when contracted by a mother during pregnancy. Rubella is the correct answer because it is specifically associated with causing birth defects such as deafness, intellectual disabilities, blindness, and heart disease in the embryo. Syphilis (Choice B) can be passed from mother to fetus but does not cause the mentioned birth defects associated with Rubella. Cystic fibrosis (Choice C) and Phenylketonuria (Choice D) are genetic conditions and not infections transmitted from mother to fetus, making them incorrect choices in this context.

5. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

Similar Questions