Nursing Elites

1. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

2. A newborn is 1 hour old with a respiratory rate of 50/min, a heart rate of 130/min, and an axillary temperature of 36.1°C (97°F). Which of the following actions should be taken?

• A. Give the newborn a warm bath.
• B. Apply a cap to the newborn's head.
• C. Reposition the newborn.
• D. Obtain an oxygen saturation level.

Correct answer: B

Rationale: Applying a cap to the newborn's head is the correct action in this scenario. Newborns are at risk of heat loss due to their high surface area to volume ratio, and maintaining their body temperature is crucial to prevent hypothermia. Giving a warm bath can further increase heat loss and is not recommended. Repositioning the newborn may not address the primary concern of temperature regulation. While monitoring oxygen saturation is important, addressing thermal regulation takes precedence in this situation.

3. A newborn who was born post-term is being assessed by a nurse. Which of the following findings should the nurse expect?

• A. A Rh-negative mother who has an Rh-positive infant
• B. A Rh-positive mother who has an Rh-negative infant
• C. A Rh-positive mother who has an Rh-positive infant
• D. A Rh-negative mother who has an Rh-negative infant

Correct answer: A

Rationale: The correct answer is A: 'A Rh-negative mother who has an Rh-positive infant.' In cases where the newborn is born post-term, the mismatched Rh factor between the mother (Rh-negative) and the infant (Rh-positive) can lead to hemolytic disease of the newborn. This condition occurs when maternal antibodies attack fetal red blood cells, causing hemolysis. This can result in jaundice, anemia, and other serious complications for the infant. Choices B, C, and D are incorrect because they do not reflect the mismatched Rh factor scenario that poses a risk for hemolytic disease of the newborn.

4. According to a study in the year 2013 by Fellman, if a woman is a twin, if her mother was a twin, or if she has previously borne twins, then:

• A. she will bear only monozygotic (MZ) twins.
• B. the chances of her becoming pregnant decrease.
• C. she is likely to be a healthy mother.
• D. the chances rise that she will bear twins.

Correct answer: D

Rationale: According to the study, the chances of a woman bearing twins increase if she is a twin herself, if her mother was a twin, or if she has previously borne twins. Therefore, the correct answer is D. Choice A is incorrect because the study does not specify that she will bear only monozygotic twins. Choice B is incorrect as the study does not mention any decrease in the chances of becoming pregnant. Choice C is incorrect because the study does not provide information about the woman's health status, focusing instead on the likelihood of bearing twins.

5. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

Similar Questions