Nursing Elites

1. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

2. Females with Turner syndrome:

• A. possess more thymine than cytosine.
• B. are taller than average.
• C. produce little estrogen.
• D. are more likely to give birth to twins.

Correct answer: C

Rationale: Turner syndrome is a chromosomal disorder in females characterized by short stature and underdeveloped ovaries, resulting in low estrogen production. This leads to symptoms such as delayed puberty and infertility. Choice A is incorrect because the chromosomal abnormality in Turner syndrome does not affect the thymine-cytosine ratio. Choice B is incorrect as females with Turner syndrome are typically shorter than average. Choice D is incorrect as Turner syndrome does not increase the likelihood of giving birth to twins.

3. Which of the following statements is true of a sperm cell?

• A. A sperm cell is significantly larger than an egg cell.
• B. A sperm cell contains two Y chromosomes.
• C. A sperm cell travels randomly inside a woman’s reproductive tract.
• D. A sperm cell is one of the smallest types of cells in the body.

Correct answer: D

Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.

4. A woman has experienced iron deficiency anemia during her pregnancy. She had been taking iron for 3 months before the birth. The client gave birth by cesarean 2 days earlier and has been having problems with constipation. After assisting her back to bed from the bathroom, the nurse notes that the woman’s stools are dark (greenish-black). What should the nurse’s initial action be?

• A. Perform a guaiac test and record the results.
• B. Recognize the finding as abnormal and report it to the primary health care provider.
• C. Recognize the finding as a normal result of iron therapy.
• D. Check the woman’s next stool to validate the observation.

Correct answer: C

Rationale: The nurse should recognize that dark stools are a common side effect in clients who are taking iron replacement therapy. Dark stools are a known, expected result of iron supplementation and are not indicative of a complication unless other symptoms of GI bleeding are present. A guaiac test would be necessary if there were concerns about gastrointestinal bleeding. Recognizing dark stools as a consequence of iron therapy is an essential nursing assessment skill and does not require immediate reporting. Checking the next stool to confirm the observation is unnecessary as the presence of dark stools in this context is already an expected outcome of iron supplementation.

5. Tim, a 27-year-old man, has unusually narrow shoulders, low muscle mass, and has no facial and body hair. His doctor recently prescribed testosterone replacement therapy to him. Tim is most likely suffering from:

• A. Phenylketonuria (PKU).
• B. Cystic fibrosis.
• C. Klinefelter syndrome.
• D. Huntington’s disease (HD).

Correct answer: C

Rationale: Tim's physical characteristics, such as narrow shoulders, low muscle mass, and lack of facial and body hair, are typical signs of Klinefelter syndrome, a genetic condition where males have an extra X chromosome (XXY). This leads to underdeveloped testes and reduced testosterone production, resulting in features like gynecomastia, sparse facial and body hair, and reduced muscle mass. Testosterone replacement therapy is commonly used to address the hormonal imbalance in individuals with Klinefelter syndrome. Phenylketonuria (PKU) is a metabolic disorder unrelated to the symptoms described in Tim's case. Cystic fibrosis is a genetic respiratory condition that does not present with the physical characteristics mentioned. Huntington’s disease (HD) is a neurodegenerative disorder primarily affecting motor function and cognition, not physical appearance and muscle mass.

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