Nursing Elites

1. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

2. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

3. Individuals with Klinefelter syndrome produce:

• A. less estrogen than normal males.
• B. less testosterone than normal males.
• C. less adenine than normal males.
• D. less thymine than normal males.

Correct answer: B

Rationale: Individuals with Klinefelter syndrome have an extra X chromosome (XXY), leading to reduced production of testosterone, the primary male sex hormone. This deficiency can result in various physical and developmental characteristics associated with the syndrome. Estrogen levels may actually be relatively elevated due to the imbalance between testosterone and estrogen. Choices C and D are incorrect as adenine and thymine are nucleotide bases found in DNA and are not related to hormone production.

4. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

5. Which of the following is a sexually transmitted infection that, in advanced stages, can attack major organ systems?

• A. Rubella
• B. Syphilis
• C. Cystic fibrosis
• D. Phenylketonuria

Correct answer: B

Rationale: Syphilis is the correct answer. Syphilis is a sexually transmitted infection caused by the bacterium Treponema pallidum. If left untreated, it can progress through various stages and potentially attack major organ systems, causing severe complications. Rubella, Cystic fibrosis, and Phenylketonuria are not sexually transmitted infections. Rubella is a viral infection, Cystic fibrosis is a genetic disorder affecting the lungs and digestive system, and Phenylketonuria is a genetic metabolic disorder. These conditions do not typically affect major organ systems in the same way as untreated syphilis.

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