Nursing Elites

1. A 38-week primigravida is admitted to labor and delivery after a non-reactive result on a non-stress test (NST). The nurse begins a contraction stress test (CST) with an oxytocin infusion. Which finding is most important for the nurse to report to the healthcare provider?

• A. A pattern of fetal late decelerations.
• B. Fetal heart rate accelerations with fetal movement.
• C. Absence of uterine contractions within 20 minutes.
• D. Spontaneous rupture of membranes.

Correct answer: A

Rationale: The correct answer is A: A pattern of fetal late decelerations. Late decelerations during a contraction stress test are concerning as they indicate uteroplacental insufficiency, which can pose a risk to fetal well-being. Reporting this finding to the healthcare provider is crucial for prompt intervention. Choice B, fetal heart rate accelerations with fetal movement, is a reassuring sign of fetal well-being and does not raise immediate concerns. Choice C, absence of uterine contractions within 20 minutes, may require further assessment but is not as critical as late decelerations. Choice D, spontaneous rupture of membranes, is important but not the most immediate concern during a contraction stress test.

2. A nurse on an antepartum unit is reviewing the medical records for four clients. Which of the following clients should the nurse assess first?

• A. A client who has diabetes mellitus and an HbA1c of 5.8%
• B. A client who has preeclampsia and a creatinine level of 1.1 mg/dL
• C. A client who has hyperemesis gravidarum and a sodium level of 110 mEq/L
• D. A client who has placenta previa and a hematocrit of 36%

Correct answer: C

Rationale: A sodium level of 110 mEq/L is critically low and can indicate severe dehydration and electrolyte imbalance, requiring immediate intervention.

3. A client is preparing to administer methylergonovine 0.2 mg orally to a client who is 2 hr postpartum and has a boggy uterus. For which of the following assessment findings should the nurse withhold the medication?

• A. Blood pressure 142/92 mm Hg
• B. Urine output 100 mL in 1 hr
• C. Pulse 58/min
• D. Respiratory rate 14/min

Correct answer: A

Rationale: The correct answer is A. Methylergonovine can increase blood pressure, so it should be withheld if the client has hypertension. A blood pressure reading of 142/92 mm Hg indicates hypertension and is a contraindication for administering methylergonovine. Choices B, C, and D are within normal limits and not contraindications for administering this medication. Urine output, pulse rate, and respiratory rate are not factors that determine the appropriateness of administering methylergonovine in this situation.

4. The nurse is caring for a multiparous client who is 8 centimeters dilated, 100% effaced, and the fetal head is at 0 station. The client is shivering and states extreme discomfort with the urge to bear down. Which intervention should the nurse implement?

• A. Administer IV pain medication
• B. Perform a vaginal exam
• C. Reposition to side-lying
• D. Encourage pushing with each contraction

Correct answer: C

Rationale: Repositioning the client to a side-lying position is the most appropriate intervention in this scenario. This position can help relieve pressure on the cervix and reduce the urge to push prematurely, allowing the cervix to continue dilating. Administering IV pain medication may not address the underlying cause of the discomfort, and pushing prematurely can lead to cervical trauma. Performing a vaginal exam is not necessary at this point as the client is already 8 centimeters dilated, and the fetal head is at 0 station.

5. Twins that derive from a single zygote that has split into two are called:

• A. monozygotic (MZ) twins.
• B. fraternal twins.
• C. non-identical twins.
• D. dizygotic (DZ) twins.

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

Similar Questions