Nursing Elites

1. What is the primary role of meiosis in the production of sperm and ova?

• A. To reduce the chromosome number by half
• B. To increase the chromosome number
• C. To create identical copies of chromosomes
• D. To repair damaged chromosomes

Correct answer: A

Rationale: The correct answer is A. Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of sperm and ova. Choice B is incorrect because meiosis does not increase the chromosome number. Choice C is incorrect because meiosis creates genetically diverse gametes, not identical copies of chromosomes. Choice D is incorrect because meiosis does not primarily function to repair damaged chromosomes.

2. Daisy was always unusually short for her age. She was unable to conceive a child after marriage, and upon visiting a doctor, she was prescribed estrogen replacement therapy. Daisy is most likely suffering from:

• A. Phenylketonuria (PKU).
• B. Cystic fibrosis.
• C. Turner syndrome.
• D. Huntington’s disease (HD).

Correct answer: C

Rationale: Daisy's symptoms of short stature and infertility, along with the prescription of estrogen replacement therapy, are indicative of Turner syndrome. Turner syndrome is a genetic condition in which a female is partially or completely missing one X chromosome. This results in short stature, infertility, and other physical characteristics. Phenylketonuria (PKU) is a metabolic disorder caused by a mutation in the gene responsible for the breakdown of the amino acid phenylalanine. Cystic fibrosis is a genetic disorder affecting the respiratory and digestive systems. Huntington's disease (HD) is a neurodegenerative disorder that affects muscle coordination and leads to cognitive decline.

3. After a mother was diagnosed with gonorrhea immediately after delivery, what is an important goal of the nurse when providing care for her baby?

• A. Prevent the development of ophthalmia neonatorum.
• B. Lubricate the eyes.
• C. Prevent the development of infection.
• D. Teach about the risks of breastfeeding with gonorrhea.

Correct answer: A

Rationale: The correct answer is A: Prevent the development of ophthalmia neonatorum. When a mother has gonorrhea, the baby can be infected during delivery, leading to ophthalmia neonatorum, which can cause permanent blindness. Therefore, it is crucial for the nurse to prevent this condition by treating the baby's eyes with an antibiotic prophylactically after birth. Choice B, lubricating the eyes, is not the primary goal in this situation as preventing infection takes precedence. Choice C, preventing the development of infection, is too broad and does not specifically address the potential complication of ophthalmia neonatorum. Choice D, teaching about the risks of breastfeeding with gonorrhea, is important but not the immediate goal in this scenario where preventing ophthalmia neonatorum and potential blindness is the priority.

4. A client is experiencing preterm labor and has a prescription for 4 doses of dexamethasone 6 mg IM every 12 hours. The available concentration is dexamethasone 10 mg/mL. How many mL of dexamethasone should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use trailing zero.)

• A. 0.6 mL
• B. ---
• C. ---
• D. ---

Correct answer: A

Rationale: Calculation: (6 mg/dose) / (10 mg/mL) = 0.6 mL per dose. The correct answer is 0.6 mL. This calculation is obtained by dividing the dose needed (6 mg) by the concentration available (10 mg/mL). The resulting value is 0.6 mL per dose. Choices B, C, and D are not applicable as the correct answer has been calculated accurately.

5. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

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