Nursing Elites

1. A primiparous woman presents in labor with the following labs: hemoglobin 10.9 g/dL, hematocrit 29%, hepatitis surface antigen positive, Group B Streptococcus positive, and rubella non-immune. Which intervention should the nurse implement?

• A. Transfuse 2 units of packed red blood cells.
• B. Give measles, mumps, rubella vaccine 0.5 mL.
• C. Administer ampicillin 2 grams intravenously.
• D. Inject hepatitis B immune globulin 0.5 milliliters.

Correct answer: C

Rationale: The correct intervention in this scenario is to administer ampicillin 2 grams intravenously. This is crucial to prevent Group B Streptococcus infection in the newborn during delivery. Option A, transfusing packed red blood cells, is not indicated based on the hemoglobin and hematocrit levels provided. Option B, giving measles, mumps, rubella vaccine, is not necessary at this time. Option D, injecting hepatitis B immune globulin, is not appropriate for the conditions presented in the question.

2. A woman with gestational diabetes has had little or no experience reading and interpreting glucose levels. The client shows the nurse her readings for the past few days. Which reading signals the nurse that the client may require an adjustment of insulin or carbohydrates?

• A. 75 mg/dl before lunch. This is low; better eat now.
• B. 115 mg/dl 1 hour after lunch. This is a little high; maybe eat a little less next time.
• C. 115 mg/dl 2 hours after lunch. This is too high; it is time for insulin.
• D. 50 mg/dl just after waking up from a nap. This is too low; maybe eat a snack before going to sleep.

Correct answer: D

Rationale: 50 mg/dl after waking from a nap is too low. During hours of sleep, glucose levels should not be less than 60 mg/dl. Snacks before sleeping can be helpful. The premeal acceptable range is 60 to 99 mg/dl. The readings 1 hour after a meal should be less than 129 mg/dl. Two hours after eating, the readings should be less than 120 mg/dl.

3. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

4. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

5. If an individual receives a recessive gene for eye color from both parents, the:

• A. gender of the child will not determine the expression of that trait.
• B. recessive trait will be expressed in the child.
• C. recessive trait will be expressed in all the offspring.
• D. recessive trait will be suppressed, and the dominant trait will not be expressed.

Correct answer: B

Rationale: When an individual inherits a recessive gene for eye color from both parents, the recessive trait will be expressed in the child. This is because having two copies of the recessive gene overrides the presence of any dominant gene. Choice A is incorrect because the expression of the trait is determined by the genetic makeup, not the gender of the child. Choice C is incorrect as the expression of the recessive trait is certain when both parents pass on the recessive gene, but it does not mean that all offspring will express the trait. Choice D is incorrect because if both parents provide a recessive gene, the dominant trait will not be expressed in the child, but it does not mean it will be suppressed; rather, the recessive trait will be expressed.

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