Nursing Elites

1. According to a study in 2014 by Skakkebaek et al., who among the following is most likely to have gynecomastia?

• A. Jennifer, a dancer, who has Down syndrome
• B. Frank, a teacher, who is diagnosed with XYY syndrome
• C. Peter, a fashion designer, who has Klinefelter syndrome
• D. Ria, a gym instructor, who is diagnosed with Turner syndrome

Correct answer: C

Rationale: Individuals with Klinefelter syndrome have an extra X chromosome (XXY) and typically have reduced testosterone levels, which can lead to gynecomastia (enlarged breasts). This condition is not usually associated with Down syndrome (choice A), XYY syndrome (choice B), or Turner syndrome (choice D), making them less likely to have gynecomastia.

2. Following an amniocentesis, a nurse is caring for a client. The nurse should observe the client for which of the following complications?

• A. Hyperemesis
• B. Proteinuria
• C. Hypoxia
• D. Hemorrhage

Correct answer: D

Rationale: After an amniocentesis, the nurse should monitor the client for potential complications, with hemorrhage being a significant concern due to the invasive nature of the procedure. Hyperemesis (severe vomiting), proteinuria (excessive protein in the urine), and hypoxia (low oxygen levels) are not typically associated with amniocentesis and are less likely to occur compared to hemorrhage, which is a more common complication that requires prompt recognition and intervention.

3. Which of the following statements is true of sickle-cell anemia?

• A. It is typically managed with treatments such as pain relief medications.
• B. It is caused by a mutation in the beta-globin gene.
• C. It leads to the obstruction of small blood vessels and decreased oxygen delivery.
• D. It is more prevalent in individuals of African, Mediterranean, Middle Eastern, and Indian descent.

Correct answer: C

Rationale: The correct answer is C. Sickle-cell anemia results from a mutation in the beta-globin gene, causing red blood cells to become sickle-shaped. These misshapen cells can obstruct small blood vessels, leading to reduced oxygen delivery to tissues. Choices A, B, and D are incorrect because sickle-cell anemia is typically managed with treatments such as pain relief medications, hydration, and in severe cases, blood transfusions. It is caused by a specific mutation in the beta-globin gene, not by the inability to metabolize phenylalanine. Additionally, sickle-cell anemia is more prevalent in individuals of African, Mediterranean, Middle Eastern, and Indian descent, not exclusive to any specific gender.

4. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

5. In the prenatal record, the nurse should record for the pregnant client who has a 3-year-old child at home, a term birth, a miscarriage at 10 weeks’ gestation, and a set of twins who died within 24 hours:

• A. Gravida 2, para 1.
• B. Gravida 3, para 3.
• C. Gravida 4, para 2.
• D. Gravida 5, para 4.

Correct answer: C

Rationale: The correct answer is C: 'Gravida 4, para 2.' Gravida refers to the total number of pregnancies, including the current one. In this case, the client has been pregnant a total of 4 times, so gravida is 4. Para is the number of pregnancies that have reached viability, which is 2 in this case. The client has had a term birth and a set of twins who died within 24 hours, totaling 2 pregnancies that reached viability. Choices A, B, and D are incorrect because they do not accurately reflect the client's obstetric history based on the information provided.

Similar Questions