Nursing Elites

1. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

2. A client is preparing to administer methylergonovine 0.2 mg orally to a client who is 2 hr postpartum and has a boggy uterus. For which of the following assessment findings should the nurse withhold the medication?

• A. Blood pressure 142/92 mm Hg
• B. Urine output 100 mL in 1 hr
• C. Pulse 58/min
• D. Respiratory rate 14/min

Correct answer: A

Rationale: The correct answer is A. Methylergonovine can increase blood pressure, so it should be withheld if the client has hypertension. A blood pressure reading of 142/92 mm Hg indicates hypertension and is a contraindication for administering methylergonovine. Choices B, C, and D are within normal limits and not contraindications for administering this medication. Urine output, pulse rate, and respiratory rate are not factors that determine the appropriateness of administering methylergonovine in this situation.

3. A client at 27 weeks of gestation with preeclampsia is being assessed by a nurse. Which of the following findings should the nurse report to the provider?

• A. Urine protein concentration of 200 mg/24 hr.
• B. Creatinine level of 0.8 mg/dL
• C. Hemoglobin level of 14.8 g/dL
• D. Platelet count of 60,000/mm3

Correct answer: D

Rationale: A platelet count of 60,000/mm3 is significantly low and can indicate HELLP syndrome, a severe complication of preeclampsia that involves hemolysis, elevated liver enzymes, and low platelet count. HELLP syndrome requires prompt medical intervention to prevent serious maternal and fetal complications. The other findings listed are within normal limits or not directly related to the severe condition associated with HELLP syndrome.

4. A perinatal nurse is caring for a woman in the immediate postpartum period. Assessment reveals that the client is experiencing profuse bleeding. What is the most likely cause of this bleeding?

• A. Uterine atony.
• B. Uterine inversion.
• C. Vaginal hematoma.
• D. Vaginal laceration.

Correct answer: A

Rationale: Uterine atony is significant hypotonia of the uterus and is the leading cause of postpartum hemorrhage. It results in the inability of the uterus to contract effectively after delivery, leading to excessive bleeding. Uterine inversion is a rare but serious complication that involves the turning inside out of the uterus, leading to hemorrhage, but it is not the most likely cause of profuse bleeding in this scenario. Vaginal hematoma may cause bleeding but is typically associated with pain as a primary symptom rather than profuse bleeding. Vaginal lacerations can cause bleeding, but in the presence of a firm, contracted uterine fundus, uterine atony is a more likely cause of ongoing profuse bleeding in the postpartum period.

5. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

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