Nursing Elites

1. Which of the following statements is true of mutations?

• A. Mutations can only occur by chance.
• B. Mutations produce sperm and ova cells.
• C. Mutations occur through radiation or other environmental influences.
• D. Mutations help adenine combine with guanine to form the single spiral structure of DNA.

Correct answer: C

Rationale: The correct answer is C. Mutations can occur due to environmental influences such as radiation, chemicals, or other external factors, leading to changes in the DNA sequence. Choice A is incorrect because mutations can also occur due to errors in DNA replication, not solely by chance. Choice B is incorrect as mutations affect the DNA sequence itself, not the production of specific cells. Choice D is incorrect because mutations involve changes in the DNA sequence and do not specifically involve the formation of the DNA structure.

2. A primigravida arrives at the observation unit of the maternity unit because she thinks she is in labor. The nurse applies the external fetal heart monitor and determines that the fetal heart rate is 140 beats per minute and contractions are occurring irregularly every 10 to 15 minutes. Which assessment finding confirms to the nurse that the client is not in labor at this time?

• A. Membranes are intact.
• B. 2+ pitting edema in lower extremities.
• C. Contractions decrease with walking.
• D. Cervical dilation is 1 centimeter.

Correct answer: C

Rationale: The correct answer is C. Contractions that decrease with walking are typically indicative of false labor, as true labor contractions tend to intensify with activity. Choices A, B, and D are incorrect. A) Intact membranes are a normal finding and do not confirm the absence of labor. B) 2+ pitting edema in lower extremities is a sign of fluid retention and not directly related to labor status. D) Cervical dilation of 1 centimeter indicates some cervical changes, but it alone does not confirm active labor.

3. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

4. A newborn is being assessed by a nurse who was born post-term. Which of the following findings should the nurse expect?

• A. Nails extending over tips of fingers
• B. Large deposits of subcutaneous fat
• C. Pale, translucent skin
• D. Thin covering of fine hair on shoulders and back

Correct answer: A

Rationale: Post-term newborns often have longer nails that extend over the tips of their fingers due to the extended gestation period. This occurs because the baby continues to grow in utero past the typical 40 weeks of gestation. Choices B, C, and D are incorrect as large deposits of subcutaneous fat, pale translucent skin, and a thin covering of fine hair on shoulders and back are not typically associated with post-term newborns. Longer nails are a common finding in post-term newborns due to the prolonged time spent in the womb, allowing for more nail growth compared to infants born at term.

5. A woman with gestational diabetes has had little or no experience reading and interpreting glucose levels. The client shows the nurse her readings for the past few days. Which reading signals the nurse that the client may require an adjustment of insulin or carbohydrates?

• A. 75 mg/dl before lunch. This is low; better eat now.
• B. 115 mg/dl 1 hour after lunch. This is a little high; maybe eat a little less next time.
• C. 115 mg/dl 2 hours after lunch. This is too high; it is time for insulin.
• D. 50 mg/dl just after waking up from a nap. This is too low; maybe eat a snack before going to sleep.

Correct answer: D

Rationale: 50 mg/dl after waking from a nap is too low. During hours of sleep, glucose levels should not be less than 60 mg/dl. Snacks before sleeping can be helpful. The premeal acceptable range is 60 to 99 mg/dl. The readings 1 hour after a meal should be less than 129 mg/dl. Two hours after eating, the readings should be less than 120 mg/dl.

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