Nursing Elites

1. A healthcare professional is caring for a client who is 14 weeks of gestation. At which of the following locations should the healthcare professional place the Doppler device when assessing the fetal heart rate?

• A. Midline 2 to 3 cm (0.8 to 1.2 in) above the symphysis pubis
• B. Left Upper Abdomen
• C. Two fingerbreadths above the umbilicus
• D. Lateral at the Xiphoid Process

Correct answer: A

Rationale: At 14 weeks of gestation, the uterus is still relatively low in the abdomen. Placing the Doppler midline 2 to 3 cm above the symphysis pubis is appropriate for assessing the fetal heart rate. This location allows for better detection of the fetal heart tones as the uterus is at a lower position during this stage of pregnancy. Placing the Doppler on the left upper abdomen would not be ideal at 14 weeks gestation as the uterus is not yet at that level. Placing it two fingerbreadths above the umbilicus or lateral at the xiphoid process would also not be accurate for locating the fetal heart rate at this stage of gestation.

2. After meiosis, each new cell nucleus contains _____ chromosomes.

• A. 46
• B. 35
• C. 23
• D. 12

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

3. Twins that derive from a single zygote that has split into two are called:

• A. monozygotic (MZ) twins.
• B. fraternal twins.
• C. non-identical twins.
• D. dizygotic (DZ) twins.

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

4. A 25-year-old gravida 3, para 2 client gave birth to a 9-pound, 7-ounce boy 4 hours ago after augmentation of labor with oxytocin (Pitocin). She presses her call light and asks for her nurse right away, stating 'I’m bleeding a lot.' What is the most likely cause of postpartum hemorrhage in this client?

• A. Retained placental fragments.
• B. Unrepaired vaginal lacerations.
• C. Uterine atony.
• D. Puerperal infection.

Correct answer: C

Rationale: Uterine atony is the most likely cause of bleeding 4 hours after delivery, especially after delivering a macrosomic infant and augmenting labor with oxytocin. Uterine atony is characterized by the inability of the uterine muscles to contract effectively after childbirth, leading to excessive bleeding. The other options, such as retained placental fragments (A), unrepaired vaginal lacerations (B), and puerperal infection (D), are less likely causes of postpartum hemorrhage in this scenario. Retained placental fragments can cause bleeding, but this typically presents earlier than 4 hours postpartum. Unrepaired vaginal lacerations would likely be evident sooner and not typically result in significant bleeding. Puerperal infection is not a common cause of immediate postpartum hemorrhage unless there are other signs of infection present.

5. A client who is 24 weeks gestation arrives at the clinic reporting swollen hands. On examination, the nurse notes the client has had a rapid weight gain over six weeks. Which action should the nurse implement next?

• A. Review the client's previous blood pressures in the chart.
• B. Obtain the client's blood pressure.
• C. Observe and time the client's contractions.
• D. Examine the client for pedal edema.

Correct answer: B

Rationale: Swollen hands and rapid weight gain could be signs of preeclampsia, so the next step is to check the client's blood pressure. Elevated blood pressure is a key indicator in assessing for preeclampsia in pregnancy. Reviewing the client's previous blood pressures may provide additional context but obtaining the current blood pressure is crucial for immediate assessment. Observing and timing contractions are not relevant in this scenario as the client is not presenting with signs of active labor. Examining for pedal edema is important in assessing for fluid retention, but obtaining the blood pressure takes precedence in this case due to the potential seriousness of preeclampsia.

Similar Questions