monozygotic mz twins share percent of their genes
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1. Monozygotic (MZ) twins share _________ percent of their genes.

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

2. What is the typical sex chromosome pattern for males?

Correct answer: C

Rationale: The correct answer is C: XY. In males, the typical sex chromosome pattern consists of one X chromosome and one Y chromosome. Choice A (XX) is the sex chromosome pattern for females. Choice B (XYY) is a chromosomal disorder where males have an extra Y chromosome. Choice D (XXY) is the sex chromosome pattern associated with Klinefelter syndrome, a condition where males have an extra X chromosome.

3. A primiparous woman presents in labor with the following labs: hemoglobin 10.9 g/dL, hematocrit 29%, hepatitis surface antigen positive, Group B Streptococcus positive, and rubella non-immune. Which intervention should the nurse implement?

Correct answer: C

Rationale: The correct intervention in this scenario is to administer ampicillin 2 grams intravenously. This is crucial to prevent Group B Streptococcus infection in the newborn during delivery. Option A, transfusing packed red blood cells, is not indicated based on the hemoglobin and hematocrit levels provided. Option B, giving measles, mumps, rubella vaccine, is not necessary at this time. Option D, injecting hepatitis B immune globulin, is not appropriate for the conditions presented in the question.

4. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

5. A client is experiencing sore nipples from breastfeeding. Which of the following actions should the nurse take?

Correct answer: B

Rationale: Ensuring the newborn's mouth is wide open before latching is crucial for achieving a proper latch, which can help reduce nipple soreness. Placing a snug dressing on the nipple when not breastfeeding (choice A) can lead to further irritation and hinder healing. Encouraging the client to limit the newborn’s feeding to 10 minutes on each breast (choice C) may not be adequate for effective feeding as infants should feed until they are satisfied. Instructing the client to begin feeding with the most tender nipple (choice D) can worsen the soreness as it may not allow the baby to feed effectively.

Similar Questions

Which of the following pairs share 100% of their genes?
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A client at 38 weeks of gestation has a prescription for intravaginal misoprostol. Which of the following statements should the nurse make?
Preconception counseling is crucial for the safe management of diabetic pregnancies. Which complication is commonly associated with poor glycemic control before and during early pregnancy?

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