Nursing Elites

1. Which of the following is most likely to develop sickle cell anemia?

• A. European American
• B. Native American
• C. African American
• D. Asian American

Correct answer: C

Rationale: Sickle cell anemia is most commonly found in individuals of African American descent. This is because sickle cell trait provides some protection against malaria, and historically, regions where malaria is or was prevalent have higher rates of sickle cell anemia. Therefore, individuals with African ancestry are at a higher risk of developing sickle cell anemia compared to other populations. Choices A, B, and D are less likely to develop sickle cell anemia due to lower genetic prevalence in their respective populations.

2. A nurse is caring for a newborn who is 6 hours old and has a bedside glucometer reading of 65 mg/dL. The newborn’s mother has type 2 diabetes mellitus. Which of the following actions should the nurse take?

• A. Obtain a blood sample for a serum glucose level
• B. Feed the newborn immediately
• C. Administer 50 mL of dextrose solution IV
• D. Reassess the blood glucose level prior to the next feeding

Correct answer: D

Rationale: A bedside glucometer reading of 65 mg/dL is within the normal range for a newborn. Reassessing the blood glucose level prior to the next feeding ensures ongoing monitoring without unnecessary intervention. Obtaining a blood sample for a serum glucose level (Choice A) is not necessary as the initial reading is normal. Feeding the newborn immediately (Choice B) may not be indicated and could lead to unnecessary interventions. Administering dextrose solution IV (Choice C) is not warranted as the glucose level is within the normal range and does not require immediate correction.

3. What is the process in which the double helix of deoxyribonucleic acid (DNA) duplicates?

• A. Amniocentesis
• B. Mitosis
• C. Meiosis
• D. Mutation

Correct answer: B

Rationale: Mitosis is the correct answer because it is the process of cell division in which a cell duplicates its DNA and divides into two identical daughter cells. During mitosis, the DNA is replicated, and each daughter cell receives an identical copy of the genetic material. Amniocentesis is a medical procedure to collect amniotic fluid for prenatal genetic testing and is not related to DNA duplication. Meiosis is a type of cell division that produces gametes with half the genetic material of the parent cell, leading to genetic diversity. Mutation is a permanent alteration in the DNA sequence that can lead to genetic variations but is not the process of DNA duplication.

4. The healthcare provider prescribes 10 units per liter of oxytocin via IV drip to augment a client's labor because she is experiencing a prolonged active phase. Which finding would cause the nurse to immediately discontinue the oxytocin?

• A. Contraction duration of 100 seconds.
• B. Four contractions in 10 minutes.
• C. Uterus is soft.
• D. Early deceleration of fetal heart rate.

Correct answer: A

Rationale: A contraction duration of 100 seconds is too long and can indicate uterine hyperstimulation, which can lead to fetal distress and other complications. This prolonged contraction duration suggests that the uterus is not relaxing adequately between contractions, potentially compromising fetal oxygenation. Choice B, 'Four contractions in 10 minutes,' is a sign of tachysystole, which is concerning but not as immediately critical as the prolonged contraction duration. Choice C, 'Uterus is soft,' is not a reason to discontinue oxytocin; in fact, it is a normal finding. Choice D, 'Early deceleration of fetal heart rate,' while indicating fetal distress, is not a direct result of the oxytocin and may require intervention but not immediate discontinuation of the medication.

5. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

Similar Questions