Nursing Elites

1. A healthcare provider is assessing a newborn upon admission to the nursery. Which of the following should the provider expect?

• A. Bulging Fontanels
• B. Nasal Flaring
• C. Length from head to heel of 40 cm (15.7 in)
• D. Chest circumference 2 cm (0.8 in) smaller than the head circumference

Correct answer: D

Rationale: Upon admission to the nursery, a healthcare provider should expect the newborn's chest circumference to be slightly smaller than the head circumference. This is a normal finding in newborns due to their physiological development. Bulging fontanels (Choice A) can indicate increased intracranial pressure, which is abnormal. Nasal flaring (Choice B) is a sign of respiratory distress and is also an abnormal finding. While a length from head to heel of 40 cm (15.7 in) (Choice C) falls within the normal range for newborns, it is not a specific expectation upon admission to the nursery. Therefore, the correct expectation for a newborn upon admission is for the chest circumference to be slightly smaller than the head circumference.

2. Rh incompatibility occurs when an Rh-negative woman is carrying an Rh-positive fetus.

• A. TRUE
• B. FALSE
• C. Sometimes
• D. Never

Correct answer: B

Rationale: Rh incompatibility occurs when an Rh-negative woman is carrying an Rh-positive fetus, not the other way around. Therefore, the statement that an Rh-positive woman is carrying an Rh-negative fetus is incorrect. Rh incompatibility can lead to hemolytic disease of the newborn, where maternal antibodies attack the fetal red blood cells. Choice A is incorrect because the statement is false. Choice C is incorrect as Rh incompatibility has a clear cause and effect relationship. Choice D is incorrect as Rh incompatibility can occur, but it depends on the Rh status of the mother and fetus.

3. According to a study in the year 2013 by Fellman, if a woman is a twin, if her mother was a twin, or if she has previously borne twins, then:

• A. she will bear only monozygotic (MZ) twins.
• B. the chances of her becoming pregnant decrease.
• C. she is likely to be a healthy mother.
• D. the chances rise that she will bear twins.

Correct answer: D

Rationale: According to the study, the chances of a woman bearing twins increase if she is a twin herself, if her mother was a twin, or if she has previously borne twins. Therefore, the correct answer is D. Choice A is incorrect because the study does not specify that she will bear only monozygotic twins. Choice B is incorrect as the study does not mention any decrease in the chances of becoming pregnant. Choice C is incorrect because the study does not provide information about the woman's health status, focusing instead on the likelihood of bearing twins.

4. Humans begin life as a single cell that divides repeatedly. This cell is known as a(n):

• A. zygote.
• B. gonadotrope.
• C. embryo.
• D. chromaffin.

Correct answer: A

Rationale: A zygote is the correct answer. It is the initial cell formed when a sperm cell fertilizes an egg cell, marking the beginning of human development. Choice B, gonadotrope, is incorrect as it refers to a type of hormone-secreting cell in the pituitary gland. Choice C, embryo, is incorrect as it is the stage of development after the zygote has implanted into the uterine wall and undergone initial cell divisions. Choice D, chromaffin, is incorrect as it refers to cells found in the adrenal medulla that produce and store catecholamines.

5. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

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