Nursing Elites

1. A client at 26 weeks gestation was informed this morning that she has an elevated alpha-fetoprotein (AFP) level. After the healthcare provider leaves the room, the client asks what she should do next. What information should the nurse provide?

• A. Reassure the client that the AFP results are likely to be a false reading.
• B. Explain that a sonogram should be scheduled for definitive results.
• C. Inform her that a repeat alpha-fetoprotein (AFP) test should be evaluated.
• D. Discuss options for intrauterine surgical correction of congenital defects.

Correct answer: B

Rationale: An elevated AFP level during pregnancy can indicate potential fetal anomalies. Further evaluation is necessary to confirm the findings and assess the need for additional interventions. Scheduling a sonogram is the appropriate next step as it can provide more definitive results and help identify any underlying issues. Choice A is incorrect because dismissing the elevated AFP level as a false reading without further investigation can lead to missing important information about the baby's health. Choice C is not the best immediate action, as scheduling a sonogram would provide more detailed information than just repeating the AFP test. Choice D is incorrect as discussing intrauterine surgical correction is premature at this stage and not typically indicated based solely on an elevated AFP level.

2. When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.

• A. monozygous
• B. dizygous
• C. homozygous
• D. hemizygous

Correct answer: C

Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.

3. The nurse has received a report regarding a client in labor. The woman’s last vaginal examination was recorded as 3 cm, 30%, and –2. What is the nurse’s interpretation of this assessment?

• A. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm above the ischial spines.
• B. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines.
• C. Cervix is effaced 3 cm and dilated 30%; the presenting part is 2 cm below the ischial spines.
• D. Cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm below the ischial spines.

Correct answer: B

Rationale: The correct interpretation of the assessment provided is that the cervix is dilated 3 cm and effaced 30%; the presenting part is 2 cm above the ischial spines. In the given assessment, the measurements are ordered as dilation, effacement, and station. Choice A is incorrect as it wrongly places the presenting part below the ischial spines. Choice C is incorrect because it places the presenting part below the ischial spines. Choice D is also incorrect as it incorrectly states that the presenting part is below the ischial spines, even though it correctly mentions the dilation and effacement of the cervix.

4. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

5. What is the primary role of meiosis in the production of sperm and ova?

• A. To reduce the chromosome number by half
• B. To increase the chromosome number
• C. To create identical copies of chromosomes
• D. To repair damaged chromosomes

Correct answer: A

Rationale: The correct answer is A. Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of sperm and ova. Choice B is incorrect because meiosis does not increase the chromosome number. Choice C is incorrect because meiosis creates genetically diverse gametes, not identical copies of chromosomes. Choice D is incorrect because meiosis does not primarily function to repair damaged chromosomes.

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