Nursing Elites

1. The healthcare provider prescribes 10 units per liter of oxytocin via IV drip to augment a client's labor because she is experiencing a prolonged active phase. Which finding would cause the nurse to immediately discontinue the oxytocin?

• A. Contraction duration of 100 seconds.
• B. Four contractions in 10 minutes.
• C. Uterus is soft.
• D. Early deceleration of fetal heart rate.

Correct answer: A

Rationale: A contraction duration of 100 seconds is too long and can indicate uterine hyperstimulation, which can lead to fetal distress and other complications. This prolonged contraction duration suggests that the uterus is not relaxing adequately between contractions, potentially compromising fetal oxygenation. Choice B, 'Four contractions in 10 minutes,' is a sign of tachysystole, which is concerning but not as immediately critical as the prolonged contraction duration. Choice C, 'Uterus is soft,' is not a reason to discontinue oxytocin; in fact, it is a normal finding. Choice D, 'Early deceleration of fetal heart rate,' while indicating fetal distress, is not a direct result of the oxytocin and may require intervention but not immediate discontinuation of the medication.

2. A client with hyperemesis gravidarum is being cared for by a nurse. Which of the following laboratory tests should the nurse anticipate?

• A. Urine Ketones
• B. Rapid plasma reagin
• C. Prothrombin time
• D. Urine culture

Correct answer: A

Rationale: Urine ketones should be anticipated as a laboratory test for a client with hyperemesis gravidarum because it helps assess the severity of dehydration and malnutrition, which are common complications of this condition. Choice B, rapid plasma reagin, is a test for syphilis and is not relevant to hyperemesis gravidarum. Choice C, prothrombin time, is a measure of blood clotting function and is not typically indicated for hyperemesis gravidarum. Choice D, urine culture, is used to identify bacteria in the urine and is not directly related to assessing dehydration and malnutrition in clients with hyperemesis gravidarum.

3. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

4. A primigravida at 36 weeks gestation who is RH-negative experienced abdominal trauma in a motor vehicle collision. Which assessment finding is most important for the nurse to report to the healthcare provider?

• A. Fetal heart rate at 162 beats per minute
• B. Mild contractions every 10 minutes
• C. Trace of protein in the urine
• D. Positive fetal hemoglobin testing

Correct answer: D

Rationale: The correct answer is 'Positive fetal hemoglobin testing' (D). Positive fetal hemoglobin testing (Kleihauer-Betke test) indicates fetal-maternal hemorrhage, which is critical in an RH-negative mother due to the risk of isoimmunization. This condition can lead to sensitization of the mother's immune system against fetal blood cells, potentially causing hemolytic disease of the newborn in subsequent pregnancies. Reporting this finding promptly is crucial for appropriate management and interventions. Choices A, B, and C are not as critical in this scenario. While monitoring fetal heart rate and contractions is important, the detection of fetal-maternal hemorrhage takes precedence due to the serious implications it poses for the current and future pregnancies of an RH-negative mother.

5. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

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