Nursing Elites

1. At 12 hours after the birth of a healthy infant, the mother complains of feeling constant vaginal pressure. The nurse determines the fundus is firm and at midline with moderate rubra lochia. Which action should the nurse take?

• A. Check the suprapubic area for distention
• B. Inform the client to take a warm sitz bath
• C. Inspect the client's perineal and rectal areas
• D. Apply a fresh pad and check in 1 hour

Correct answer: C

Rationale: In this situation, the mother's complaint of constant vaginal pressure along with a firm fundus and moderate rubra lochia indicates a potential perineal injury or hematoma. The correct action for the nurse to take is to inspect the client's perineal and rectal areas to assess for any signs of trauma or hematoma. Checking the suprapubic area for distention (Choice A) is not the priority here since the symptoms suggest a perineal issue. Advising a warm sitz bath (Choice B) may not address the underlying issue and could potentially worsen any existing trauma. Applying a fresh pad and checking in 1 hour (Choice D) does not address the need for immediate assessment of the perineal and rectal areas in response to the reported symptoms.

2. Which of the following statements is true of sickle-cell anemia?

• A. It is typically managed with treatments such as pain relief medications.
• B. It is caused by a mutation in the beta-globin gene.
• C. It leads to the obstruction of small blood vessels and decreased oxygen delivery.
• D. It is more prevalent in individuals of African, Mediterranean, Middle Eastern, and Indian descent.

Correct answer: C

Rationale: The correct answer is C. Sickle-cell anemia results from a mutation in the beta-globin gene, causing red blood cells to become sickle-shaped. These misshapen cells can obstruct small blood vessels, leading to reduced oxygen delivery to tissues. Choices A, B, and D are incorrect because sickle-cell anemia is typically managed with treatments such as pain relief medications, hydration, and in severe cases, blood transfusions. It is caused by a specific mutation in the beta-globin gene, not by the inability to metabolize phenylalanine. Additionally, sickle-cell anemia is more prevalent in individuals of African, Mediterranean, Middle Eastern, and Indian descent, not exclusive to any specific gender.

3. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

4. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

5. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

Similar Questions