HESI LPN
HESI Maternal Newborn
1. A 16-year-old gravida 1 para 0 client has just been admitted to the hospital with a diagnosis of eclampsia. She's not presently convulsing. Which intervention should the nurse plan to include in this client's nursing care plan?
- A. Allow liberal family visitation
- B. Keep an airway at the bedside
- C. Assess temperature every hour
- D. Monitor blood pressure, pulse, and respiration every 4 hours
Correct answer: B
Rationale: Keeping an airway at the bedside is crucial for a client with eclampsia, as there is a high risk of seizures that can obstruct the airway. Allowing liberal family visitation (choice A) may not be a priority at this time and can be overwhelming for the client. Assessing temperature every hour (choice C) is not directly related to managing eclampsia. Monitoring blood pressure, pulse, and respiration every 4 hours (choice D) is important but not as immediate as ensuring airway patency.
2. A perinatal nurse is caring for a woman in the immediate postpartum period. Assessment reveals that the client is experiencing profuse bleeding. What is the most likely cause of this bleeding?
- A. Uterine atony.
- B. Uterine inversion.
- C. Vaginal hematoma.
- D. Vaginal laceration.
Correct answer: A
Rationale: Uterine atony is significant hypotonia of the uterus and is the leading cause of postpartum hemorrhage. It results in the inability of the uterus to contract effectively after delivery, leading to excessive bleeding. Uterine inversion is a rare but serious complication that involves the turning inside out of the uterus, leading to hemorrhage, but it is not the most likely cause of profuse bleeding in this scenario. Vaginal hematoma may cause bleeding but is typically associated with pain as a primary symptom rather than profuse bleeding. Vaginal lacerations can cause bleeding, but in the presence of a firm, contracted uterine fundus, uterine atony is a more likely cause of ongoing profuse bleeding in the postpartum period.
3. A client is receiving an epidural block with an opioid analgesic. The nurse should monitor for which of the following findings as an adverse effect of the medication?
- A. Hypotension
- B. Polyuria
- C. Bilateral crackles
- D. Hyperglycemia
Correct answer: C
Rationale: The correct answer is C: Bilateral crackles. Bilateral crackles indicate respiratory complications, which can occur as an adverse effect of an epidural block with opioid analgesics. Hypotension (Choice A) is a common side effect of epidural opioids but is not typically monitored via crackles. Polyuria (Choice B) is excessive urination and is not directly associated with epidural blocks. Hyperglycemia (Choice D) is high blood sugar levels and is not a typical adverse effect of epidural opioids.
4. Before meiosis, a sperm cell:
- A. contains 46 chromosomes.
- B. contains two X chromosomes.
- C. is significantly larger than an egg cell.
- D. contains both an X and a Y chromosome.
Correct answer: A
Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.
5. According to a study in the year 2013 by Fellman, if a woman is a twin, if her mother was a twin, or if she has previously borne twins, then:
- A. she will bear only monozygotic (MZ) twins.
- B. the chances of her becoming pregnant decrease.
- C. she is likely to be a healthy mother.
- D. the chances rise that she will bear twins.
Correct answer: D
Rationale: According to the study, the chances of a woman bearing twins increase if she is a twin herself, if her mother was a twin, or if she has previously borne twins. Therefore, the correct answer is D. Choice A is incorrect because the study does not specify that she will bear only monozygotic twins. Choice B is incorrect as the study does not mention any decrease in the chances of becoming pregnant. Choice C is incorrect because the study does not provide information about the woman's health status, focusing instead on the likelihood of bearing twins.
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