Nursing Elites

1. When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.

• A. monozygous
• B. dizygous
• C. homozygous
• D. hemizygous

Correct answer: C

Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.

2. What nursing action should the nurse implement for a 3-hour-old male infant who presents with cyanotic hands and feet, an axillary temperature of 96.5°F (35.8°C), a respiratory rate of 40 breaths per minute, and a heart rate of 165 beats per minute?

• A. Administer oxygen by mouth at 2L/min
• B. Gradually warm the infant under a radiant heat source
• C. Notify the pediatrician of the infant's vital signs
• D. Perform a heel-stick to maintain blood glucose levels

Correct answer: B

Rationale: The correct nursing action is to gradually warm the infant under a radiant heat source. The infant is presenting with signs of cold stress, indicated by cyanotic extremities and a low body temperature. Gradual warming is crucial to stabilize the infant's temperature and prevent further complications. Administering oxygen, notifying the pediatrician, or performing a heel-stick are not the priority actions in this scenario and may not address the immediate need to raise the infant's body temperature.

3. When reviewing the electronic medical record of a postpartum client, which of the following factors places the client at risk for infection?

• A. Meconium-stained amniotic fluid
• B. Placenta previa
• C. Midline episiotomy
• D. Gestational hypertension

Correct answer: C

Rationale: The correct answer is C: Midline episiotomy. An episiotomy is a surgical incision made during childbirth to enlarge the vaginal opening. This procedure increases the risk of infection in the postpartum period due to the incision site being a potential entry point for pathogens. Meconium-stained amniotic fluid (choice A) is a risk factor for fetal distress but does not directly increase the mother's risk of infection. Placenta previa (choice B) is a condition where the placenta partially or completely covers the cervix, leading to potential bleeding issues but not necessarily an increased risk of infection. Gestational hypertension (choice D) is a hypertensive disorder that affects some pregnant women but is not directly associated with an increased risk of infection in the postpartum period.

4. A client is 4 hours postpartum and is experiencing hypovolemic shock. Which of the following actions should the nurse take?

• A. Administer indomethacin
• B. Insert a second 22-gauge IV catheter.
• C. Insert an indwelling urinary catheter.
• D. Administer oxygen at 4L/min via nasal cannula.

Correct answer: D

Rationale: In hypovolemic shock, there is decreased oxygen delivery to tissues. Administering oxygen at 4L/min via nasal cannula can help improve oxygenation and support tissue perfusion. Indomethacin (Choice A) is a nonsteroidal anti-inflammatory drug and is not indicated in the management of hypovolemic shock. Inserting a second 22-gauge IV catheter (Choice B) may be necessary for fluid resuscitation, but oxygen administration takes precedence. Inserting an indwelling urinary catheter (Choice C) may be considered for monitoring urinary output, but it is not the priority action in managing hypovolemic shock.

5. What is the typical sex chromosome pattern for males?

• A. XX
• B. XYY
• C. XY
• D. XXY

Correct answer: C

Rationale: The correct answer is C: XY. In males, the typical sex chromosome pattern consists of one X chromosome and one Y chromosome. Choice A (XX) is the sex chromosome pattern for females. Choice B (XYY) is a chromosomal disorder where males have an extra Y chromosome. Choice D (XXY) is the sex chromosome pattern associated with Klinefelter syndrome, a condition where males have an extra X chromosome.

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