Nursing Elites

1. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

2. What is the primary role of meiosis in the production of sperm and ova?

• A. To reduce the chromosome number by half
• B. To increase the chromosome number
• C. To create identical copies of chromosomes
• D. To repair damaged chromosomes

Correct answer: A

Rationale: The correct answer is A. Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of sperm and ova. Choice B is incorrect because meiosis does not increase the chromosome number. Choice C is incorrect because meiosis creates genetically diverse gametes, not identical copies of chromosomes. Choice D is incorrect because meiosis does not primarily function to repair damaged chromosomes.

3. A woman has experienced iron deficiency anemia during her pregnancy. She had been taking iron for 3 months before the birth. The client gave birth by cesarean 2 days earlier and has been having problems with constipation. After assisting her back to bed from the bathroom, the nurse notes that the woman’s stools are dark (greenish-black). What should the nurse’s initial action be?

• A. Perform a guaiac test and record the results.
• B. Recognize the finding as abnormal and report it to the primary health care provider.
• C. Recognize the finding as a normal result of iron therapy.
• D. Check the woman’s next stool to validate the observation.

Correct answer: C

Rationale: The nurse should recognize that dark stools are a common side effect in clients who are taking iron replacement therapy. Dark stools are a known, expected result of iron supplementation and are not indicative of a complication unless other symptoms of GI bleeding are present. A guaiac test would be necessary if there were concerns about gastrointestinal bleeding. Recognizing dark stools as a consequence of iron therapy is an essential nursing assessment skill and does not require immediate reporting. Checking the next stool to confirm the observation is unnecessary as the presence of dark stools in this context is already an expected outcome of iron supplementation.

4. Which of the following illnesses causes degeneration of the central nervous system?

• A. Tay-Sachs disease
• B. Cystic fibrosis
• C. Turner syndrome
• D. Klinefelter syndrome

Correct answer: A

Rationale: Tay-Sachs disease is a genetic disorder that causes a progressive degeneration of the central nervous system, particularly in infants. Choice B, Cystic fibrosis, is a genetic disorder that primarily affects the lungs and digestive system, not the central nervous system. Choices C and D, Turner syndrome and Klinefelter syndrome, are chromosomal disorders that do not directly involve degeneration of the central nervous system.

5. According to a survey by Adhikari and Liu in the year 2013, at birth, women have:

• A. close to 100,000 ova.
• B. around 300,000 to 400,000 ova.
• C. around 100 to 200 ova.
• D. only 500 ova.

Correct answer: B

Rationale: Women are born with approximately 300,000 to 400,000 ova, which gradually decrease in number as they age. Choice A ('close to 100,000 ova.') is incorrect as the actual number is much higher. Choice C ('around 100 to 200 ova.') is incorrect as it underestimates the quantity significantly. Choice D ('only 500 ova.') is incorrect as it greatly underestimates the number of ova present at birth.

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