Nursing Elites

1. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

2. A perinatal nurse is caring for a woman in the immediate postpartum period. Assessment reveals that the client is experiencing profuse bleeding. What is the most likely cause of this bleeding?

• A. Uterine atony.
• B. Uterine inversion.
• C. Vaginal hematoma.
• D. Vaginal laceration.

Correct answer: A

Rationale: Uterine atony is significant hypotonia of the uterus and is the leading cause of postpartum hemorrhage. It results in the inability of the uterus to contract effectively after delivery, leading to excessive bleeding. Uterine inversion is a rare but serious complication that involves the turning inside out of the uterus, leading to hemorrhage, but it is not the most likely cause of profuse bleeding in this scenario. Vaginal hematoma may cause bleeding but is typically associated with pain as a primary symptom rather than profuse bleeding. Vaginal lacerations can cause bleeding, but in the presence of a firm, contracted uterine fundus, uterine atony is a more likely cause of ongoing profuse bleeding in the postpartum period.

3. A charge nurse is teaching a group of staff nurses about fetal monitoring during labor. Which of the following findings should the charge nurse instruct the staff members to report to the provider?

• A. Contraction durations of 95 to 100 seconds
• B. Contraction frequency of 2 to 3 minutes apart
• C. Absent early deceleration of fetal heart rate
• D. Fetal heart rate is 140/min

Correct answer: A

Rationale: The correct answer is A. Contraction durations of 95 to 100 seconds are prolonged, indicating uterine hyperstimulation, which can lead to fetal distress and requires immediate intervention. Reporting this finding to the provider is crucial to ensure timely management and prevent adverse outcomes. Choice B, contraction frequency of 2 to 3 minutes apart, is within the normal range and does not raise immediate concerns. Choice C, absent early deceleration of fetal heart rate, is a reassuring finding suggesting fetal well-being. Choice D, a fetal heart rate of 140/min, is also normal for a fetus and does not typically require immediate reporting unless it deviates significantly from the baseline or is accompanied by other concerning signs.

4. What information should the nurse include when teaching a client at 41 weeks of gestation about a non-stress test?

• A. This test will confirm fetal lung maturity.
• B. This test will determine the adequacy of placental perfusion.
• C. This test will detect fetal infection.
• D. This test will predict maternal readiness for labor.

Correct answer: B

Rationale: The correct answer is B: 'This test will determine the adequacy of placental perfusion.' The non-stress test is used to assess fetal well-being by monitoring the fetal heart rate in response to its own movements. It helps determine if the fetus is receiving enough oxygen and nutrients through placental perfusion. Choice A is incorrect because confirming fetal lung maturity is typically determined through tests like amniocentesis, not the non-stress test. Choice C is incorrect because detecting fetal infection is not the primary purpose of a non-stress test. Choice D is incorrect because predicting maternal readiness for labor is not the purpose of the non-stress test; it focuses on fetal well-being.

5. Which of the following statements is true of a sperm cell?

• A. A sperm cell is significantly larger than an egg cell.
• B. A sperm cell contains two Y chromosomes.
• C. A sperm cell travels randomly inside a woman’s reproductive tract.
• D. A sperm cell is one of the smallest types of cells in the body.

Correct answer: D

Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.

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