Nursing Elites

1. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

2. A newborn assessment reveals spina bifida occulta. Which maternal factor should the nurse identify as having the greatest impact on the development of this newborn complication?

• A. Tobacco use.
• B. Folic acid deficiency.
• C. Short interval between pregnancies.
• D. Preeclampsia.

Correct answer: B

Rationale: Folic acid deficiency during pregnancy is strongly associated with neural tube defects like spina bifida occulta. Adequate folic acid intake before and during early pregnancy significantly reduces the risk of such complications. Tobacco use (Choice A) is linked to other adverse outcomes but not specifically spina bifida occulta. Short intervals between pregnancies (Choice C) can increase the risk of preterm birth and low birth weight but are not directly linked to spina bifida occulta. Preeclampsia (Choice D) is a hypertensive disorder that poses risks to both the mother and baby but is not the primary factor contributing to spina bifida occulta development.

3. A primigravida arrives at the observation unit of the maternity unit because she thinks she is in labor. The nurse applies the external fetal heart monitor and determines that the fetal heart rate is 140 beats per minute and contractions are occurring irregularly every 10 to 15 minutes. Which assessment finding confirms to the nurse that the client is not in labor at this time?

• A. Membranes are intact.
• B. 2+ pitting edema in lower extremities.
• C. Contractions decrease with walking.
• D. Cervical dilation is 1 centimeter.

Correct answer: C

Rationale: The correct answer is C. Contractions that decrease with walking are typically indicative of false labor, as true labor contractions tend to intensify with activity. Choices A, B, and D are incorrect. A) Intact membranes are a normal finding and do not confirm the absence of labor. B) 2+ pitting edema in lower extremities is a sign of fluid retention and not directly related to labor status. D) Cervical dilation of 1 centimeter indicates some cervical changes, but it alone does not confirm active labor.

4. What causes cystic fibrosis?

• A. Sex-linked abnormality.
• B. Abnormality in the 21st pair of chromosomes.
• C. Recessive gene.
• D. Single segment found only on the Y chromosome.

Correct answer: C

Rationale: Cystic fibrosis is a genetic disorder caused by inheriting two copies of a recessive gene, one from each parent. This means that both parents must carry at least one copy of the faulty gene for a child to inherit the condition. Choice A is incorrect because cystic fibrosis is not linked to the sex chromosomes. Choice B is incorrect as cystic fibrosis is not caused by an abnormality in the 21st pair of chromosomes but by a specific gene mutation. Choice D is also incorrect as cystic fibrosis is not related to the Y chromosome, which is specific to males.

5. When obtaining a health history from a client, a nurse in a woman’s health clinic should identify which of the following findings as increasing the client’s risk for developing pelvic inflammatory disease (PID)?

• A. Recurrent Cystitis
• B. Frequent Alcohol Use
• C. Use of Oral Contraceptives
• D. Chlamydia Infection

Correct answer: D

Rationale: Chlamydia infection is a significant risk factor for developing pelvic inflammatory disease (PID). PID is often caused by untreated sexually transmitted infections (STIs) like Chlamydia and Gonorrhea that ascend from the vagina to the upper reproductive organs. Recurrent cystitis (choice A) is more related to urinary tract infections, frequent alcohol use (choice B) is not directly linked to PID, and the use of oral contraceptives (choice C) does not increase the risk of developing PID.

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