which of the following statements is true of a sperm cell
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Nursing Elites

HESI LPN

HESI Focus on Maternity Exam

1. Which of the following statements is true of a sperm cell?

Correct answer: D

Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.

2. Monozygotic (MZ) twins share _________ percent of their genes.

Correct answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

3. What nursing diagnosis is the most appropriate for a woman experiencing severe preeclampsia?

Correct answer: A

Rationale: The most appropriate nursing diagnosis for a woman experiencing severe preeclampsia is 'Risk for injury to mother and fetus, related to central nervous system (CNS) irritability.' Severe preeclampsia poses a significant risk of injury to both the mother and the fetus due to complications such as seizures, stroke, and placental abruption. 'Risk for altered gas exchange' is not the priority diagnosis as pulmonary edema is more common in severe preeclampsia. 'Risk for deficient fluid volume' is incorrect as sodium retention in severe preeclampsia often leads to fluid overload. 'Risk for increased cardiac output' is also incorrect as antihypertensive drugs are used to reduce cardiac output in this condition.

4. When obtaining a health history from a client, a nurse in a woman’s health clinic should identify which of the following findings as increasing the client’s risk for developing pelvic inflammatory disease (PID)?

Correct answer: D

Rationale: Chlamydia infection is a significant risk factor for developing pelvic inflammatory disease (PID). PID is often caused by untreated sexually transmitted infections (STIs) like Chlamydia and Gonorrhea that ascend from the vagina to the upper reproductive organs. Recurrent cystitis (choice A) is more related to urinary tract infections, frequent alcohol use (choice B) is not directly linked to PID, and the use of oral contraceptives (choice C) does not increase the risk of developing PID.

5. A 30-year-old primigravida delivers a nine-pound (4082 gram) infant vaginally after a 30-hour labor. What is the priority nursing action for this client?

Correct answer: C

Rationale: After a prolonged labor and delivery of a large infant, the client is at an increased risk for uterine atony and postpartum hemorrhage, making observation for signs of bleeding a priority. Assessing the blood pressure for hypertension (Choice A) is not the priority in this situation as the immediate concern is postpartum hemorrhage. Gently massaging the fundus every four hours (Choice B) is a routine postpartum care activity but is not the priority in this scenario. Encouraging direct contact with the infant (Choice D) is important for bonding but does not address the immediate risk of uterine hemorrhage after delivery.

Similar Questions

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