HESI LPN
HESI Focus on Maternity Exam
1. Which of the following statements is true of a sperm cell?
- A. A sperm cell is significantly larger than an egg cell.
- B. A sperm cell contains two Y chromosomes.
- C. A sperm cell travels randomly inside a woman’s reproductive tract.
- D. A sperm cell is one of the smallest types of cells in the body.
Correct answer: D
Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.
2. If an individual receives a recessive gene for eye color from both parents, the:
- A. gender of the child will not determine the expression of that trait.
- B. recessive trait will be expressed in the child.
- C. recessive trait will be expressed in all the offspring.
- D. recessive trait will be suppressed, and the dominant trait will not be expressed.
Correct answer: B
Rationale: When an individual inherits a recessive gene for eye color from both parents, the recessive trait will be expressed in the child. This is because having two copies of the recessive gene overrides the presence of any dominant gene. Choice A is incorrect because the expression of the trait is determined by the genetic makeup, not the gender of the child. Choice C is incorrect as the expression of the recessive trait is certain when both parents pass on the recessive gene, but it does not mean that all offspring will express the trait. Choice D is incorrect because if both parents provide a recessive gene, the dominant trait will not be expressed in the child, but it does not mean it will be suppressed; rather, the recessive trait will be expressed.
3. According to a study in 2014 by Skakkebaek et al., who among the following is most likely to have gynecomastia?
- A. Jennifer, a dancer, who has Down syndrome
- B. Frank, a teacher, who is diagnosed with XYY syndrome
- C. Peter, a fashion designer, who has Klinefelter syndrome
- D. Ria, a gym instructor, who is diagnosed with Turner syndrome
Correct answer: C
Rationale: Individuals with Klinefelter syndrome have an extra X chromosome (XXY) and typically have reduced testosterone levels, which can lead to gynecomastia (enlarged breasts). This condition is not usually associated with Down syndrome (choice A), XYY syndrome (choice B), or Turner syndrome (choice D), making them less likely to have gynecomastia.
4. What nursing diagnosis is the most appropriate for a woman experiencing severe preeclampsia?
- A. Risk for injury to mother and fetus, related to central nervous system (CNS) irritability.
- B. Risk for altered gas exchange.
- C. Risk for deficient fluid volume, related to increased sodium retention secondary to the administration of magnesium sulfate.
- D. Risk for increased cardiac output, related to the use of antihypertensive drugs.
Correct answer: A
Rationale: The most appropriate nursing diagnosis for a woman experiencing severe preeclampsia is 'Risk for injury to mother and fetus, related to central nervous system (CNS) irritability.' Severe preeclampsia poses a significant risk of injury to both the mother and the fetus due to complications such as seizures, stroke, and placental abruption. 'Risk for altered gas exchange' is not the priority diagnosis as pulmonary edema is more common in severe preeclampsia. 'Risk for deficient fluid volume' is incorrect as sodium retention in severe preeclampsia often leads to fluid overload. 'Risk for increased cardiac output' is also incorrect as antihypertensive drugs are used to reduce cardiac output in this condition.
5. Four clients at full term present to the labor and delivery unit at the same time. Which client should a nurse assess first?
- A. Multipara with contractions occurring every three minutes
- B. Multipara scheduled for non-stress test and biophysical profile
- C. Primipara with vaginal show and leaking membranes
- D. Primipara with burning on urination and urinary frequency
Correct answer: C
Rationale: A primipara with vaginal show and leaking membranes requires immediate assessment as she may be in active labor or at risk of infection. The vaginal show and leaking membranes suggest potential rupture of membranes and the start of labor. Assessing her first ensures prompt management and monitoring. The other options, while important, do not indicate immediate or emergent needs. Contractions every three minutes in a multipara can be managed with ongoing monitoring; non-stress tests and biophysical profiles can be scheduled and are not acute needs. Burning on urination and urinary frequency in a primipara may indicate a urinary tract infection, which is important but not as urgent as assessing for active labor or rupture of membranes.
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