Nursing Elites

1. Which information regarding the care of antepartum women with cardiac conditions is most important for the nurse to understand?

• A. Stress on the heart is greatest in the first trimester and the last 2 weeks before labor.
• B. Women with class II cardiac disease should avoid heavy exertion and any activity that causes even minor symptoms.
• C. Women with class III cardiac disease should get 8 to 10 hours of sleep every day and limit housework, shopping, and exercise.
• D. Women with class I cardiac disease need bed rest through most of the pregnancy and face the possibility of hospitalization near term.

Correct answer: B

Rationale: Class II cardiac disease is symptomatic with ordinary activity. Women in this category need to avoid heavy exertion and limit regular activities as symptoms dictate. Stress is greatest between weeks 28 and 32 of gestation, when hemodynamic changes reach their maximum. Class III cardiac disease is symptomatic with less-than-ordinary activity. These women need bed rest most of the day and face the possibility of hospitalization near term. Class I cardiac disease is asymptomatic at normal levels of activity. These women can perform limited normal activities with discretion, although they still need a good amount of sleep.

2. In the prenatal record, the nurse should record for the pregnant client who has a 3-year-old child at home, a term birth, a miscarriage at 10 weeks’ gestation, and a set of twins who died within 24 hours:

• A. Gravida 2, para 1.
• B. Gravida 3, para 3.
• C. Gravida 4, para 2.
• D. Gravida 5, para 4.

Correct answer: C

Rationale: The correct answer is C: 'Gravida 4, para 2.' Gravida refers to the total number of pregnancies, including the current one. In this case, the client has been pregnant a total of 4 times, so gravida is 4. Para is the number of pregnancies that have reached viability, which is 2 in this case. The client has had a term birth and a set of twins who died within 24 hours, totaling 2 pregnancies that reached viability. Choices A, B, and D are incorrect because they do not accurately reflect the client's obstetric history based on the information provided.

3. After meiosis, each new cell nucleus contains _____ chromosomes.

• A. 46
• B. 35
• C. 23
• D. 12

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

4. A client is receiving an epidural block with an opioid analgesic. The nurse should monitor for which of the following findings as an adverse effect of the medication?

• A. Hypotension
• B. Polyuria
• C. Bilateral crackles
• D. Hyperglycemia

Correct answer: C

Rationale: The correct answer is C: Bilateral crackles. Bilateral crackles indicate respiratory complications, which can occur as an adverse effect of an epidural block with opioid analgesics. Hypotension (Choice A) is a common side effect of epidural opioids but is not typically monitored via crackles. Polyuria (Choice B) is excessive urination and is not directly associated with epidural blocks. Hyperglycemia (Choice D) is high blood sugar levels and is not a typical adverse effect of epidural opioids.

5. When both of the alleles for a trait, such as hair color, are the same, the person is said to be _____ for that trait.

• A. monozygous
• B. dizygous
• C. homozygous
• D. hemizygous

Correct answer: C

Rationale: A person is homozygous for a trait when they have two identical alleles for that trait. In this case, both alleles are the same, indicating a homozygous genotype. Choice A, 'monozygous,' is incorrect as it refers to identical twins originating from a single fertilized egg. Choice B, 'dizygous,' is also incorrect as it refers to fraternal twins or individuals that develop from two separate fertilized eggs. Choice D, 'hemizygous,' is incorrect because it describes a genetic condition where only one allele is present in a diploid organism, typically related to genes on the sex chromosomes.

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