Nursing Elites

1. Which information regarding the care of antepartum women with cardiac conditions is most important for the nurse to understand?

• A. Stress on the heart is greatest in the first trimester and the last 2 weeks before labor.
• B. Women with class II cardiac disease should avoid heavy exertion and any activity that causes even minor symptoms.
• C. Women with class III cardiac disease should get 8 to 10 hours of sleep every day and limit housework, shopping, and exercise.
• D. Women with class I cardiac disease need bed rest through most of the pregnancy and face the possibility of hospitalization near term.

Correct answer: B

Rationale: Class II cardiac disease is symptomatic with ordinary activity. Women in this category need to avoid heavy exertion and limit regular activities as symptoms dictate. Stress is greatest between weeks 28 and 32 of gestation, when hemodynamic changes reach their maximum. Class III cardiac disease is symptomatic with less-than-ordinary activity. These women need bed rest most of the day and face the possibility of hospitalization near term. Class I cardiac disease is asymptomatic at normal levels of activity. These women can perform limited normal activities with discretion, although they still need a good amount of sleep.

2. What determines a child’s sex?

• A. Presence of teratogens at the time of conception.
• B. Sex chromosome received from the mother.
• C. Presence of teratogens at the time of ovulation.
• D. Sex chromosome received from the father.

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

3. A client with preeclampsia is receiving magnesium sulfate by continuous IV infusion. Which finding should the nurse report to the provider?

• A. Blood pressure 148/94 mm Hg
• B. Respiratory rate 14/min
• C. Urinary output 20 mL/hr
• D. 2+ deep tendon reflexes

Correct answer: C

Rationale: In a client with preeclampsia receiving magnesium sulfate, a urinary output of 20 mL/hr is a concerning finding as it may indicate renal impairment or magnesium toxicity. Adequate urinary output is crucial for eliminating excess magnesium and preventing toxicity. The nurse should report this finding to the provider for further evaluation. A blood pressure of 148/94 mm Hg is elevated but expected in a client with preeclampsia. A respiratory rate of 14/min is within the normal range. 2+ deep tendon reflexes are a common finding in clients receiving magnesium sulfate and are not a cause for concern unless they progress to hyperreflexia or clonus.

4. A client who is at 24 weeks of gestation is receiving teaching about expected changes during pregnancy. Which of the following information should the nurse include?

• A. Your stomach will empty rapidly
• B. You should expect your uterus to double in size
• C. You should anticipate nasal stuffiness
• D. Your nipples will become lighter in color

Correct answer: C

Rationale: Nasal stuffiness is a common symptom during pregnancy due to increased blood flow and hormonal changes. This symptom is caused by the increased blood volume and hormonal changes that lead to swelling of the nasal passages. Choices A, B, and D are incorrect. Stomach emptying rate does not significantly change during pregnancy; the uterus does not double in size at 24 weeks but rather grows steadily, and nipples typically darken in color due to increased pigmentation.

5. Before meiosis, a sperm cell:

• A. contains 46 chromosomes.
• B. contains two X chromosomes.
• C. is significantly larger than an egg cell.
• D. contains both an X and a Y chromosome.

Correct answer: A

Rationale: Before meiosis, a sperm cell contains 46 chromosomes. This is because sperm cells, like other somatic cells, have a diploid number of chromosomes. During meiosis, the number of chromosomes is halved to 23 to combine with an egg cell during fertilization. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not both (Choice D). Choice C is incorrect as sperm cells are generally smaller than egg cells, which is an adaptation that aids in motility and penetration of the egg during fertilization.

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