a nurse is caring for a client who is at 20 weeks of gestation and has trichomoniasis which of the following findings should the nurse expect
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1. A client at 20 weeks of gestation has trichomoniasis. Which of the following findings should the nurse expect?

Correct answer: D

Rationale: Malodorous discharge is a common symptom of trichomoniasis caused by the Trichomonas vaginalis parasite. It is typically described as frothy, greenish-yellow, and malodorous. Choices A, B, and C are incorrect findings associated with other conditions. Thick, white vaginal discharge is more characteristic of a yeast infection; urinary frequency may be seen in urinary tract infections; and vulvar lesions are commonly seen in herpes simplex virus infections.

2. Which of the following pairs share 100% of their genes?

Correct answer: D

Rationale: The correct answer is Monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, share 100% of their genes because they originate from the same fertilized egg that splits into two. Fraternal twins (choice B), also known as dizygotic (DZ) twins (choice C), result from two separate fertilized eggs and share approximately 50% of their genes. Biovular twins (choice A) is not a term used in genetics and does not describe a type of twinning.

3. When should the low-risk patient, who is 16 weeks pregnant, be advised to return to the prenatal clinic?

Correct answer: D

Rationale: The correct answer is D: 4 weeks. Low-risk pregnant patients typically have prenatal visits every 4 weeks until 28 weeks of gestation. This frequency allows for adequate monitoring of the pregnancy without being overly burdensome on the patient. Choices A, B, and C are incorrect as they do not align with the standard prenatal care schedule for low-risk pregnancies. Visits that are too frequent may cause unnecessary anxiety for the patient, while visits that are too infrequent may miss important opportunities for monitoring and intervention.

4. At 31 weeks gestation, a client with a fundal height measurement of 25 cm is scheduled for a series of ultrasounds to be performed every two weeks. Which explanation should the nurse provide?

Correct answer: C

Rationale: The correct answer is C: 'Evaluation of fetal growth.' A fundal height measurement smaller than expected may indicate intrauterine growth restriction (IUGR), requiring serial ultrasounds to monitor fetal growth. Assessing for congenital anomalies (choice A) is usually done through detailed anatomy scans earlier in pregnancy. Recalculating gestational age (choice B) is typically unnecessary at this stage unless there are concerns about accuracy. Determining fetal presentation (choice D) is usually done closer to term to plan for the mode of delivery.

5. What determines a child’s sex?

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

Similar Questions

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