Nursing Elites

1. The nurse is receiving a report for a laboring client who arrived in the emergency center with ruptured membranes that the client did not recognize. Which is the priority nursing action to implement when the client is admitted to the labor and delivery suite?

• A. Begin a pad count
• B. Prepare to start an IV
• C. Take the client's temperature
• D. Monitor amniotic fluid for meconium

Correct answer: C

Rationale: The priority nursing action when a client with ruptured membranes is admitted to the labor and delivery suite is to take the client's temperature. This is crucial to assess for infection, especially when the duration of membrane rupture is unknown. Beginning a pad count, preparing to start an IV, and monitoring amniotic fluid for meconium are important actions but are not as immediate or critical as assessing for infection through temperature measurement.

2. After meiosis, each new cell nucleus contains _____ chromosomes.

• A. 46
• B. 35
• C. 23
• D. 12

Correct answer: C

Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.

3. When obtaining a health history from a client, a nurse in a woman’s health clinic should identify which of the following findings as increasing the client’s risk for developing pelvic inflammatory disease (PID)?

• A. Recurrent Cystitis
• B. Frequent Alcohol Use
• C. Use of Oral Contraceptives
• D. Chlamydia Infection

Correct answer: D

Rationale: Chlamydia infection is a significant risk factor for developing pelvic inflammatory disease (PID). PID is often caused by untreated sexually transmitted infections (STIs) like Chlamydia and Gonorrhea that ascend from the vagina to the upper reproductive organs. Recurrent cystitis (choice A) is more related to urinary tract infections, frequent alcohol use (choice B) is not directly linked to PID, and the use of oral contraceptives (choice C) does not increase the risk of developing PID.

4. Which of the following conditions is considered a multifactorial problem?

• A. Cystic fibrosis
• B. Down syndrome
• C. Diabetes mellitus
• D. XYY syndrome

Correct answer: C

Rationale: The correct answer is 'Diabetes mellitus' because it is a multifactorial disease, influenced by both genetic predisposition and environmental factors. Cystic fibrosis (choice A) is primarily a genetic disorder caused by mutations in the CFTR gene. Down syndrome (choice B) is due to an extra copy of chromosome 21. XYY syndrome (choice D) is a genetic condition where males have an extra Y chromosome. These conditions are not considered multifactorial as their origins are primarily genetic.

5. Does the probability of having a child with Down’s syndrome increase with the age of the parents?

• A. TRUE
• B. FALSE
• C. Sometimes
• D. Never

Correct answer: A

Rationale: The correct answer is A: TRUE. Advanced parental age, particularly maternal age, is associated with an increased risk of Down's syndrome in offspring. As parents get older, the likelihood of having a child with Down's syndrome increases. Choices B, C, and D are incorrect because the risk of Down's syndrome is known to rise with parental age, especially maternal age, due to the increased likelihood of chromosomal abnormalities during egg formation.

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