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Maternity HESI Practice Questions
1. If an individual receives a recessive gene for eye color from both parents, the:
- A. gender of the child will not determine the expression of that trait.
- B. recessive trait will be expressed in the child.
- C. recessive trait will be expressed in all the offspring.
- D. recessive trait will be suppressed, and the dominant trait will not be expressed.
Correct answer: B
Rationale: When an individual inherits a recessive gene for eye color from both parents, the recessive trait will be expressed in the child. This is because having two copies of the recessive gene overrides the presence of any dominant gene. Choice A is incorrect because the expression of the trait is determined by the genetic makeup, not the gender of the child. Choice C is incorrect as the expression of the recessive trait is certain when both parents pass on the recessive gene, but it does not mean that all offspring will express the trait. Choice D is incorrect because if both parents provide a recessive gene, the dominant trait will not be expressed in the child, but it does not mean it will be suppressed; rather, the recessive trait will be expressed.
2. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:
- A. a carrier of the recessive gene that causes the disease.
- B. susceptible to the disease after adolescence.
- C. an acceptor of the recessive gene that causes the disease.
- D. susceptible to the disease in late adulthood.
Correct answer: A
Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.
3. A woman at 26 weeks of gestation is being assessed to determine whether she is experiencing preterm labor. Which finding indicates that preterm labor is occurring?
- A. Estriol is not found in maternal saliva.
- B. Irregular, mild uterine contractions occur every 12 to 15 minutes.
- C. Fetal fibronectin is present in vaginal secretions.
- D. The cervix is effacing and dilated to 2 cm.
Correct answer: D
Rationale: The correct answer is D. Cervical changes such as effacement and dilation to 2 cm are strong indicators of imminent preterm labor. These changes, combined with regular contractions, can signify labor at any gestation. Estriol can be detected in maternal plasma as early as 9 weeks of gestation. Levels of salivary estriol have been linked to preterm birth. Irregular, mild contractions occurring every 12 to 15 minutes without cervical change are generally not concerning. While the presence of fetal fibronectin in vaginal secretions between 24 and 36 weeks of gestation may predict preterm labor, its predictive value is limited (20%-40%). Therefore, cervical changes provide more reliable information regarding the risk of preterm labor.
4. When children who are reared by adoptive parents are nonetheless more similar to their natural parents in a trait, it can be concluded that:
- A. the genetic characteristics of the children change over time.
- B. heredity is solely responsible for how a child grows.
- C. the environment is solely responsible for the development of those characteristics.
- D. genetics play a role in the development of those characteristics.
Correct answer: D
Rationale: When children exhibit traits that are more similar to their biological parents than their adoptive parents, it indicates a strong genetic influence on those traits. This similarity suggests that genetics play a significant role in the development of the observed characteristics. Choice A is incorrect because genetic characteristics do not change over time in this context. Choice B is incorrect as it implies that heredity is the only factor, disregarding the impact of the environment. Choice C is also incorrect as it suggests that only the environment influences trait development, overlooking the genetic contribution.
5. What is a procedure for using ultrasonic sound waves to create a picture of an embryo or fetus?
- A. Phenotype
- B. Sonogram
- C. Genotype
- D. Alpha-fetoprotein (AFP) assay
Correct answer: B
Rationale: A sonogram, also known as an ultrasound, is a procedure that utilizes sound waves to generate images of a developing embryo or fetus. This imaging technique is commonly used in prenatal care to monitor fetal development and identify any potential abnormalities. Choices A, C, and D are incorrect because a phenotype refers to an individual's observable traits resulting from genetic and environmental influences, a genotype is an individual's genetic makeup, and an alpha-fetoprotein (AFP) assay is a blood test used to screen for certain birth defects.
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