Nursing Elites

1. Daisy was always unusually short for her age. She was unable to conceive a child after marriage, and upon visiting a doctor, she was prescribed estrogen replacement therapy. Daisy is most likely suffering from:

• A. Phenylketonuria (PKU).
• B. Cystic fibrosis.
• C. Turner syndrome.
• D. Huntington’s disease (HD).

Correct answer: C

Rationale: Daisy's symptoms of short stature and infertility, along with the prescription of estrogen replacement therapy, are indicative of Turner syndrome. Turner syndrome is a genetic condition in which a female is partially or completely missing one X chromosome. This results in short stature, infertility, and other physical characteristics. Phenylketonuria (PKU) is a metabolic disorder caused by a mutation in the gene responsible for the breakdown of the amino acid phenylalanine. Cystic fibrosis is a genetic disorder affecting the respiratory and digestive systems. Huntington's disease (HD) is a neurodegenerative disorder that affects muscle coordination and leads to cognitive decline.

2. When assessing a woman in the first stage of labor, which clinical finding will alert the nurse that uterine contractions are effective?

• A. Dilation of the cervix.
• B. Descent of the fetus to –2 station.
• C. Rupture of the amniotic membranes.
• D. Increase in bloody show.

Correct answer: A

Rationale: During the first stage of labor, effective uterine contractions lead to cervical dilation. Dilation of the cervix is a key indicator that uterine contractions are progressing labor. Descent of the fetus to -2 station (Choice B) is related to the fetal position in the pelvis and not a direct indicator of uterine contraction effectiveness. Rupture of the amniotic membranes (Choice C) signifies the rupture of the fluid-filled sac surrounding the fetus and does not directly reflect uterine contraction effectiveness. An increase in bloody show (Choice D) can be a sign of impending labor, but it is not a direct indicator of uterine contraction effectiveness.

3. A client in labor requests nonpharmacological pain management. Which of the following nursing actions promotes client comfort?

• A. Assisting the client into a squatting position
• B. Having the client lie in a supine position
• C. Applying fundal pressure during contractions
• D. Encouraging the client to void every 6 hours

Correct answer: A

Rationale: Assisting the client into a squatting position promotes comfort during labor. This position can help relieve pain by utilizing gravity, allowing the pelvic outlet to widen, and potentially facilitating the progress of labor. Lying in a supine position (Choice B) can hinder labor progression and increase discomfort. Applying fundal pressure (Choice C) can be inappropriate and may cause harm as it is not routinely recommended during labor. Encouraging the client to void every 6 hours (Choice D) is important for bladder management but does not directly address pain relief during labor.

4. A client at 38 weeks of gestation has a prescription for intravaginal misoprostol. Which of the following statements should the nurse make?

• A. “You will need to stay in a side-lying position for 30 minutes after each dose.”
• B. “You will receive an IV infusion of oxytocin 1 hour after your last dose.”
• C. “You will receive a magnesium supplement immediately following therapy.”
• D. “You will need to have a full bladder before the therapy begins.”

Correct answer: A

Rationale: The correct answer is A. Instructing the client to stay in a side-lying position after receiving misoprostol intravaginally is essential. This position helps keep the medication in place, allowing for better absorption. Choice B is incorrect because oxytocin administration is not typically indicated after misoprostol use. Choice C is incorrect as magnesium supplementation is not part of the standard protocol for misoprostol administration. Choice D is incorrect as having a full bladder is not necessary before initiating misoprostol therapy.

5. What is the primary role of meiosis in the production of sperm and ova?

• A. To reduce the chromosome number by half
• B. To increase the chromosome number
• C. To create identical copies of chromosomes
• D. To repair damaged chromosomes

Correct answer: A

Rationale: The correct answer is A. Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of sperm and ova. Choice B is incorrect because meiosis does not increase the chromosome number. Choice C is incorrect because meiosis creates genetically diverse gametes, not identical copies of chromosomes. Choice D is incorrect because meiosis does not primarily function to repair damaged chromosomes.

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