HESI LPN
HESI Maternal Newborn
1. A primigravida is being monitored at the prenatal clinic for preeclampsia. Which finding is of greatest concern to the nurse?
- A. Blood pressure (BP) increased to 138/86 mm Hg.
- B. Weight gain of 0.5 kg during the past 2 weeks.
- C. Dipstick value of 3+ for protein in her urine.
- D. Pitting pedal edema at the end of the day.
Correct answer: C
Rationale: The correct answer is C. Proteinuria, indicated by a dipstick value of 3+ in the urine, is a significant concern in a patient being monitored for preeclampsia. Proteinuria is a key diagnostic criterion for preeclampsia, and a value of 3+ signifies a substantial amount of protein in the urine, warranting further evaluation. While an increase in blood pressure to 138/86 mm Hg is slightly elevated, it does not meet the diagnostic threshold for severe hypertension in preeclampsia. A weight gain of 0.5 kg over 2 weeks is within normal limits and not as concerning as significant rapid weight gain. Pitting pedal edema, though common in pregnancy, is not a specific indicator of preeclampsia and is considered a less concerning finding compared to significant proteinuria.
2. Females with Turner syndrome:
- A. possess more thymine than cytosine.
- B. are taller than average.
- C. produce little estrogen.
- D. are more likely to give birth to twins.
Correct answer: C
Rationale: Turner syndrome is a chromosomal disorder in females characterized by short stature and underdeveloped ovaries, resulting in low estrogen production. This leads to symptoms such as delayed puberty and infertility. Choice A is incorrect because the chromosomal abnormality in Turner syndrome does not affect the thymine-cytosine ratio. Choice B is incorrect as females with Turner syndrome are typically shorter than average. Choice D is incorrect as Turner syndrome does not increase the likelihood of giving birth to twins.
3. After meiosis, each new cell nucleus contains _____ chromosomes.
- A. 46
- B. 35
- C. 23
- D. 12
Correct answer: C
Rationale: After meiosis, each resulting cell contains 23 chromosomes. Meiosis is a process that involves two sequential divisions resulting in four daughter cells, each with half the number of chromosomes as the parent cell. In humans, the parent cell has 46 chromosomes (diploid), and after meiosis, the resulting cells (sperm or ova) have 23 chromosomes (haploid). Choice A (46 chromosomes) is incorrect because this is the number of chromosomes in a human diploid cell before meiosis. Choices B (35 chromosomes) and D (12 chromosomes) are incorrect as they do not represent the correct number of chromosomes after meiosis in human cells.
4. Which of the following statements is a characteristic of supermales?
- A. They are somewhat taller than average.
- B. Their facial hair growth is minimal when compared to normal males.
- C. They suffer from gynecomastia.
- D. They are typically impotent.
Correct answer: A
Rationale: The correct characteristic of supermales, individuals with an XYY chromosome pattern, is that they are somewhat taller than average. Choice B is incorrect as supermales do not exhibit minimal facial hair growth compared to normal males. Choice C is incorrect as gynecomastia, the development of male breasts, is not a characteristic of supermales. Choice D is also incorrect as impotence is not a typical characteristic associated with supermales.
5. After a mother was diagnosed with gonorrhea immediately after delivery, what is an important goal of the nurse when providing care for her baby?
- A. Prevent the development of ophthalmia neonatorum.
- B. Lubricate the eyes.
- C. Prevent the development of infection.
- D. Teach about the risks of breastfeeding with gonorrhea.
Correct answer: A
Rationale: The correct answer is A: Prevent the development of ophthalmia neonatorum. When a mother has gonorrhea, the baby can be infected during delivery, leading to ophthalmia neonatorum, which can cause permanent blindness. Therefore, it is crucial for the nurse to prevent this condition by treating the baby's eyes with an antibiotic prophylactically after birth. Choice B, lubricating the eyes, is not the primary goal in this situation as preventing infection takes precedence. Choice C, preventing the development of infection, is too broad and does not specifically address the potential complication of ophthalmia neonatorum. Choice D, teaching about the risks of breastfeeding with gonorrhea, is important but not the immediate goal in this scenario where preventing ophthalmia neonatorum and potential blindness is the priority.
Similar Questions
Access More Features
HESI LPN Basic
$69.99/ 30 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access
HESI LPN Premium
$149.99/ 90 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access