Nursing Elites

1. A client in the transition phase of labor reports a pain level of 7 on a scale of 0 to 10. Which of the following actions should the nurse take?

• A. Instruct the client to use effleurage.
• B. Apply counterpressure to the client's sacrum.
• C. Assist the client with patterned-paced breathing.
• D. Teach the client the technique of biofeedback.

Correct answer: B

Rationale: During the transition phase of labor, a client may experience intense back pain due to the pressure of the baby descending. Applying counterpressure to the client's sacrum can help alleviate this discomfort. Effleurage is a light stroking massage technique that may not provide adequate relief for intense back pain. Patterned-paced breathing is beneficial for managing contractions but may not directly address back pain. Biofeedback is a technique that helps individuals gain awareness and control of certain physiological functions, but it may not be the most appropriate intervention for acute labor pain.

2. An individual’s phenotype reflects both genetic and environmental influences.

• A. phenotype
• B. chromosome
• C. allele
• D. genotype

Correct answer: A

Rationale: The correct answer is A: phenotype. A phenotype is the observable characteristics of an individual, which result from the interaction of their genotype with the environment. This interaction between genetics and the environment determines how genes are expressed and how traits are manifested in an individual. Choices B, C, and D are incorrect because chromosomes, alleles, and genotypes are components of an individual's genetic makeup, but they do not directly reflect the observable traits influenced by both genetics and the environment.

3. What information should the nurse include when teaching a client at 41 weeks of gestation about a non-stress test?

• A. This test will confirm fetal lung maturity.
• B. This test will determine the adequacy of placental perfusion.
• C. This test will detect fetal infection.
• D. This test will predict maternal readiness for labor.

Correct answer: B

Rationale: The correct answer is B: 'This test will determine the adequacy of placental perfusion.' The non-stress test is used to assess fetal well-being by monitoring the fetal heart rate in response to its own movements. It helps determine if the fetus is receiving enough oxygen and nutrients through placental perfusion. Choice A is incorrect because confirming fetal lung maturity is typically determined through tests like amniocentesis, not the non-stress test. Choice C is incorrect because detecting fetal infection is not the primary purpose of a non-stress test. Choice D is incorrect because predicting maternal readiness for labor is not the purpose of the non-stress test; it focuses on fetal well-being.

4. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

5. What determines a child’s sex?

• A. Presence of teratogens at the time of conception.
• B. Sex chromosome received from the mother.
• C. Presence of teratogens at the time of ovulation.
• D. Sex chromosome received from the father.

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

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