Nursing Elites

1. A client comes to the clinic for her first prenatal visit and reports that July 10 was the first day of her last menstrual period. Using Nagele’s Rule, the nurse calculates the estimated date of birth for the client to be _________.

• A. 4/17.
• B. 4/10.
• C. 5/10.
• D. 5/17.

Correct answer: A

Rationale: Nagele's Rule is a common method used to estimate the due date. To calculate it, subtract 3 months and add 7 days to the first day of the last menstrual period. In this case, if the last menstrual period started on July 10, subtracting 3 months (April) and adding 7 days gives an estimated due date of April 17. This is the correct answer. Choices B, C, and D are incorrect because they do not follow the Nagele's Rule calculation method.

2. A woman with gestational diabetes has had little or no experience reading and interpreting glucose levels. The client shows the nurse her readings for the past few days. Which reading signals the nurse that the client may require an adjustment of insulin or carbohydrates?

• A. 75 mg/dl before lunch. This is low; better eat now.
• B. 115 mg/dl 1 hour after lunch. This is a little high; maybe eat a little less next time.
• C. 115 mg/dl 2 hours after lunch. This is too high; it is time for insulin.
• D. 50 mg/dl just after waking up from a nap. This is too low; maybe eat a snack before going to sleep.

Correct answer: D

Rationale: 50 mg/dl after waking from a nap is too low. During hours of sleep, glucose levels should not be less than 60 mg/dl. Snacks before sleeping can be helpful. The premeal acceptable range is 60 to 99 mg/dl. The readings 1 hour after a meal should be less than 129 mg/dl. Two hours after eating, the readings should be less than 120 mg/dl.

3. _________ is self-propulsion.

• A. Mitosis
• B. Meiosis
• C. Motility
• D. Mutation

Correct answer: C

Rationale: The correct answer is 'Motility.' Motility refers to the ability of cells or organisms to move by themselves, often through the use of specialized structures like flagella or cilia. Mitosis (Choice A) and Meiosis (Choice B) are processes related to cell division and genetic recombination, respectively, not self-propulsion. Mutation (Choice D) refers to changes in the DNA sequence and is not related to self-propulsion.

4. What determines a child’s sex?

• A. Presence of teratogens at the time of conception.
• B. Sex chromosome received from the mother.
• C. Presence of teratogens at the time of ovulation.
• D. Sex chromosome received from the father.

Correct answer: D

Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.

5. Jill bears the genetic code for Von Willebrand disease, but she has never developed the illness herself. Jill would be considered:

• A. a carrier of the recessive gene that causes the disease.
• B. susceptible to the disease after adolescence.
• C. an acceptor of the recessive gene that causes the disease.
• D. susceptible to the disease in late adulthood.

Correct answer: A

Rationale: Jill is a carrier of the recessive gene for Von Willebrand disease. Being a carrier means that she has one copy of the gene but does not show symptoms of the disease. Carriers can pass on the gene to their offspring. Choice B is incorrect as being a carrier does not mean she is susceptible to developing the disease after adolescence. Choice C is incorrect as 'acceptor' is not a term used in genetics in this context. Choice D is incorrect as susceptibility to the disease is not related to late adulthood in carriers of a recessive gene.

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