Nursing Elites

1. A client at 34 weeks gestation comes to the birthing center complaining of vaginal bleeding that began one hour ago. The nurse's assessment reveals approximately 30ML of bright red vaginal bleeding, fetal heart rate of 130 - 140 beats per minute, no contractions, and no complaints of pain. What is the most likely cause of this client's bleeding?

• A. Abruptio Placenta
• B. Placenta Previa
• C. Normal bloody show indicating induction of labor
• D. A ruptured blood vessel in the vaginal vault

Correct answer: B

Rationale: Placenta previa, a condition where the placenta covers the cervix, can cause painless, bright red vaginal bleeding in the third trimester. In this scenario, the absence of contractions and pain, along with the presence of significant bright red bleeding, is more indicative of placenta previa rather than abruptio placenta or a ruptured vessel. A normal bloody show typically occurs closer to the onset of labor and is not associated with the amount of bleeding described in the question.

2. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

3. A nurse is developing an educational program about hemolytic diseases in newborns for a group of newly licensed nurses. Which of the following genetic information should the nurse include in the program as a cause of hemolytic disease?

• A. The mother is Rh positive, and the father is Rh negative
• B. The mother is Rh negative, and the father is Rh positive
• C. The mother and the father are both Rh positive
• D. The mother and the father are both Rh negative

Correct answer: B

Rationale: The correct answer is B: 'The mother is Rh negative, and the father is Rh positive.' Hemolytic disease of the newborn occurs when an Rh-negative mother carries an Rh-positive fetus, leading to Rh incompatibility. In this scenario, the mother produces antibodies against the Rh antigen present in the fetus, which can result in hemolysis of the fetal red blood cells. Choices A, C, and D do not describe the Rh incompatibility that leads to hemolytic disease in newborns. Therefore, they are incorrect.

4. A primiparous woman presents in labor with the following labs: hemoglobin 10.9 g/dL, hematocrit 29%, hepatitis surface antigen positive, Group B Streptococcus positive, and rubella non-immune. Which intervention should the nurse implement?

• A. Transfuse 2 units of packed red blood cells.
• B. Give measles, mumps, rubella vaccine 0.5 mL.
• C. Administer ampicillin 2 grams intravenously.
• D. Inject hepatitis B immune globulin 0.5 milliliters.

Correct answer: C

Rationale: The correct intervention in this scenario is to administer ampicillin 2 grams intravenously. This is crucial to prevent Group B Streptococcus infection in the newborn during delivery. Option A, transfusing packed red blood cells, is not indicated based on the hemoglobin and hematocrit levels provided. Option B, giving measles, mumps, rubella vaccine, is not necessary at this time. Option D, injecting hepatitis B immune globulin, is not appropriate for the conditions presented in the question.

5. Which of the following statements is true of a sperm cell?

• A. A sperm cell is significantly larger than an egg cell.
• B. A sperm cell contains two Y chromosomes.
• C. A sperm cell travels randomly inside a woman’s reproductive tract.
• D. A sperm cell is one of the smallest types of cells in the body.

Correct answer: D

Rationale: The correct answer is D. A sperm cell is indeed one of the smallest cells in the human body, much smaller than an egg cell. Choice A is incorrect as sperm cells are much smaller than egg cells. Choice B is incorrect because a sperm cell carries either an X or a Y chromosome, not two Y chromosomes. Choice C is incorrect since sperm cells move in a purposeful manner guided by various factors within a woman's reproductive tract, not randomly.

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