HESI LPN
HESI Focus on Maternity Exam
1. A charge nurse is teaching a group of staff nurses about fetal monitoring during labor. Which of the following findings should the charge nurse instruct the staff members to report to the provider?
- A. Contraction durations of 95 to 100 seconds
- B. Contraction frequency of 2 to 3 minutes apart
- C. Absent early deceleration of fetal heart rate
- D. Fetal heart rate is 140/min
Correct answer: A
Rationale: The correct answer is A. Contraction durations of 95 to 100 seconds are prolonged, indicating uterine hyperstimulation, which can lead to fetal distress and requires immediate intervention. Reporting this finding to the provider is crucial to ensure timely management and prevent adverse outcomes. Choice B, contraction frequency of 2 to 3 minutes apart, is within the normal range and does not raise immediate concerns. Choice C, absent early deceleration of fetal heart rate, is a reassuring finding suggesting fetal well-being. Choice D, a fetal heart rate of 140/min, is also normal for a fetus and does not typically require immediate reporting unless it deviates significantly from the baseline or is accompanied by other concerning signs.
2. What determines a child’s sex?
- A. Presence of teratogens at the time of conception.
- B. Sex chromosome received from the mother.
- C. Presence of teratogens at the time of ovulation.
- D. Sex chromosome received from the father.
Correct answer: D
Rationale: The correct answer is the sex chromosome received from the father. The father contributes either an X or Y chromosome, which determines the child's sex. This occurs at the moment of fertilization when the sperm carrying either an X (resulting in a female) or Y (resulting in a male) chromosome fertilizes the egg. Choices A, B, and C are incorrect because the presence of teratogens at the time of conception or ovulation does not determine the child's sex. While the sex chromosome received from the mother is important, it is the father's contribution that ultimately determines the child's sex.
3. Rubella, also called German measles, is a viral infection passed from the mother to the fetus that can cause birth defects such as deafness, intellectual disabilities, blindness, and heart disease in the embryo.
- A. Rubella
- B. Syphilis
- C. Cystic fibrosis
- D. Phenylketonuria
Correct answer: A
Rationale: Rubella, also known as German measles, is a viral infection that can lead to severe birth defects when contracted by a mother during pregnancy. Rubella is the correct answer because it is specifically associated with causing birth defects such as deafness, intellectual disabilities, blindness, and heart disease in the embryo. Syphilis (Choice B) can be passed from mother to fetus but does not cause the mentioned birth defects associated with Rubella. Cystic fibrosis (Choice C) and Phenylketonuria (Choice D) are genetic conditions and not infections transmitted from mother to fetus, making them incorrect choices in this context.
4. A client is receiving oxytocin by continuous IV infusion for labor induction. Which of the following interventions should the nurse include in the plan?
- A. Increase the infusion rate every 30 to 60 minutes.
- B. Maintain the client in a supine position.
- C. Titrate the infusion rate by 4 milliunits/min.
- D. Limit IV intake to 4 L per 24 hours.
Correct answer: A
Rationale: The correct answer is to increase the infusion rate every 30 to 60 minutes. This approach allows for the careful monitoring and adjustment of oxytocin administration during labor induction. Choice B is incorrect because maintaining the client in a supine position can decrease blood flow to the placenta and compromise fetal oxygenation. Choice C is incorrect as titrating the infusion rate by 4 milliunits/min is not a standard practice for oxytocin administration. Choice D is incorrect as limiting IV intake to 4 L per 24 hours is not specifically related to the administration of oxytocin for labor induction.
5. Females with Turner syndrome:
- A. possess more thymine than cytosine.
- B. are taller than average.
- C. produce little estrogen.
- D. are more likely to give birth to twins.
Correct answer: C
Rationale: Turner syndrome is a chromosomal disorder in females characterized by short stature and underdeveloped ovaries, resulting in low estrogen production. This leads to symptoms such as delayed puberty and infertility. Choice A is incorrect because the chromosomal abnormality in Turner syndrome does not affect the thymine-cytosine ratio. Choice B is incorrect as females with Turner syndrome are typically shorter than average. Choice D is incorrect as Turner syndrome does not increase the likelihood of giving birth to twins.
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