a 17 year old client gave birth 12 hours ago she states that she doesnt know how to care for her baby to promote parent infant attachment behaviors wh
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HESI Maternal Newborn

1. A 17-year-old client gave birth 12 hours ago. She states that she doesn't know how to care for her baby. To promote parent-infant attachment behaviors, which intervention should the nurse implement?

Correct answer: D

Rationale: Encouraging rooming in while in the hospital is the most appropriate intervention to promote parent-infant attachment behaviors. Rooming in allows the mother to stay with her baby continuously, facilitating bonding and providing the opportunity for the mother to learn how to care for her baby with the nurse's support. Asking if she has help at home (Choice A) does not directly address promoting attachment behaviors. Providing a video on newborn safety and care (Choice B) may offer information but does not actively facilitate immediate bonding. Exploring the basis of fears (Choice C) is important but may not directly address promoting attachment behaviors as effectively as encouraging rooming in.

2. The nurse places one hand above the symphysis while massaging the fundus of a multiparous client whose uterine tone is boggy 15 minutes after delivering a 7-pound, 10-ounce (3220-gram) infant. Which information should the nurse provide to the client about these findings?

Correct answer: D

Rationale: After childbirth, a boggy uterus indicates poor uterine tone, which can lead to the formation of clots. Massaging the fundus helps the uterus contract and expel clots, reducing the risk of postpartum hemorrhage. Choices A, B, and C are incorrect because the main concern with a boggy uterus is the risk of clot formation and postpartum hemorrhage, not solely preventing intrauterine infection, massaging the lower uterine segment, or preventing the endometrial lining from sloughing.

3. A client with hyperemesis gravidarum is being cared for by a nurse. Which of the following laboratory tests should the nurse anticipate?

Correct answer: A

Rationale: Urine ketones should be anticipated as a laboratory test for a client with hyperemesis gravidarum because it helps assess the severity of dehydration and malnutrition, which are common complications of this condition. Choice B, rapid plasma reagin, is a test for syphilis and is not relevant to hyperemesis gravidarum. Choice C, prothrombin time, is a measure of blood clotting function and is not typically indicated for hyperemesis gravidarum. Choice D, urine culture, is used to identify bacteria in the urine and is not directly related to assessing dehydration and malnutrition in clients with hyperemesis gravidarum.

4. A healthcare provider is reviewing laboratory results for a client who is pregnant. The healthcare provider should expect which of the following laboratory values to increase?

Correct answer: A

Rationale: During pregnancy, the body increases the production of red blood cells (RBCs) to meet the increased oxygen demands. This physiological response is known as physiological anemia of pregnancy. Therefore, the RBC count is expected to increase during pregnancy. Bilirubin levels may remain relatively stable, fasting blood glucose levels might fluctuate due to gestational diabetes, and blood urea nitrogen (BUN) levels are not typically affected by pregnancy, making them less likely to increase in this scenario. The correct answer is A because an increase in RBC count is a normal physiological adaptation to pregnancy to support the increased oxygen needs of the mother and the growing fetus. Bilirubin, a product of red blood cell breakdown, is more related to liver function and not expected to increase during pregnancy. Fasting blood glucose levels may vary due to gestational diabetes, but it is not a consistent finding in all pregnant individuals. BUN levels are related to kidney function and are not typically impacted by pregnancy, making it an unlikely choice for an expected increase in laboratory values during pregnancy.

5. Twins that derive from a single zygote that has split into two are called:

Correct answer: A

Rationale: The correct answer is A: monozygotic (MZ) twins. Monozygotic twins, also known as identical twins, occur when a single zygote splits into two embryos, leading to two genetically identical individuals. Choice B, fraternal twins, are twins that develop from two separate eggs fertilized by two different sperm cells, resulting in non-identical siblings. Choice C, non-identical twins, is not a common term used to describe this type of twinning. Choice D, dizygotic (DZ) twins, refer to twins that develop from two separate eggs fertilized by two different sperm cells, leading to non-identical twins.

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