HESI LPN
Medical Surgical Assignment Exam HESI
1. What is a causative factor of Hirschsprung disease?
- A. Frequent evacuation of solids, liquid, and gases
- B. Excessive peristaltic movement
- C. The absence of parasympathetic ganglion cells in a portion of the colon
- D. One portion of the bowel telescoping into another
Correct answer: C
Rationale: The correct answer is C: The absence of parasympathetic ganglion cells in a portion of the colon is a causative factor of Hirschsprung disease. This absence leads to the inability of the affected segment of the colon to relax, causing a functional obstruction. Choices A, B, and D are incorrect. Frequent evacuation of solids, liquid, and gases, excessive peristaltic movement, and one portion of the bowel telescoping into another are not causative factors of Hirschsprung disease.
2. The nurse uses a diagram to show that the tetralogy of Fallot involves a combination of four congenital defects. What are the defects?
- A. Aortic stenosis, atrial septal defect, overriding aorta, left ventricular hypertrophy
- B. Pulmonary stenosis, ventricular septal defect, overriding aorta, right ventricular hypertrophy
- C. Aortic stenosis, atrial septal defect, overriding aorta, right ventricular hypertrophy
- D. Pulmonary stenosis, ventricular septal defect, aortic hypertrophy, left ventricular hypertrophy
Correct answer: B
Rationale: The correct answer is B: Pulmonary stenosis, ventricular septal defect, overriding aorta, right ventricular hypertrophy. Tetralogy of Fallot involves these four congenital defects. Choice A is incorrect because it includes aortic stenosis instead of pulmonary stenosis, atrial septal defect instead of ventricular septal defect, and left ventricular hypertrophy instead of right ventricular hypertrophy. Choice C is incorrect as it includes aortic stenosis and atrial septal defect instead of pulmonary stenosis and ventricular septal defect. Choice D is incorrect because it includes aortic hypertrophy instead of overriding aorta.
3. The nurse instructs the mother of a child with a ventricular septal defect that she can expect the child to become cyanotic when the child does what?
- A. Experiences an elevation in temperature.
- B. Sleeps on the left side.
- C. Cries vigorously.
- D. Eats.
Correct answer: C
Rationale: The correct answer is C: Cries vigorously. When the child cries vigorously, it increases the pressure in the right ventricle, allowing unoxygenated blood to enter the circulating volume, leading to cyanosis. This occurs due to the shunting of blood from the right side of the heart to the left side through the ventricular septal defect. Choices A, B, and D are incorrect because they do not directly impact the pressure in the right ventricle, which is crucial in causing cyanosis in this scenario.
4. Ten hours following thrombolysis for an ST elevation myocardial infarction (STEMI), a client is receiving a lidocaine infusion for isolated runs of ventricular tachycardia. Which finding should the nurse document in the EMR as a therapeutic response to the lidocaine infusion?
- A. Stabilization of BP ranges
- B. Cessation of chest pain
- C. Reduced heart rate
- D. Decreased frequency of episodes of VT
Correct answer: D
Rationale: The correct answer is D. Decreased frequency of ventricular tachycardia (VT) episodes indicates that the lidocaine infusion is effectively managing the ventricular tachycardia. Stabilization of BP ranges (choice A) may not directly correlate with the therapeutic response to lidocaine for VT. Cessation of chest pain (choice B) may indicate pain relief but does not specifically address the effectiveness of lidocaine for VT. Reduced heart rate (choice C) is not a direct indicator of the response to lidocaine for managing VT.
5. A client with urolithiasis is preparing for discharge after lithotripsy. Which intervention should the nurse include in the client's postoperative discharge instructions?
- A. Report when hematuria becomes pink-tinged
- B. Use incentive spirometer
- C. Restrict physical activities
- D. Monitor urinary stream for a decrease in output
Correct answer: D
Rationale: After lithotripsy, monitoring the urinary stream for a decrease in output is essential to identify any potential complications such as urinary retention or obstruction. Reporting pink-tinged hematuria is important, but monitoring the urinary stream for a decrease in output takes precedence as it directly assesses renal function and potential complications. Using an incentive spirometer is not directly related to post-lithotripsy care. Restricting physical activities may be necessary initially but is not the priority compared to monitoring urinary output.
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