Nursing Elites

1. What is the most critical initial intervention for a client who is actively seizing?

• A. Restrain the client to prevent injury
• B. Insert an oral airway
• C. Turn the client to the side
• D. Apply soft restraints to the wrists

Correct answer: C

Rationale: The most critical initial intervention for a client who is actively seizing is to turn the client to the side. This action helps maintain an open airway and prevents aspiration during a seizure. Restrain the client to prevent injury (Choice A) is incorrect because restraining a client during a seizure can lead to injury. Inserting an oral airway (Choice B) is not recommended as it can cause injury and is not necessary during an active seizure. Applying soft restraints to the wrists (Choice D) is also not recommended as it can lead to harm and does not address the immediate airway management needed during a seizure.

2. A client is receiving a secondary infusion of erythromycin 1 gram in 100 mL dextrose 5% in water (D5W) to be infused in 45 minutes. How many mL/hour should the nurse program the infusion pump?

• A. 100 mL/hour.
• B. 125 mL/hour.
• C. 133 mL/hour.
• D. 150 mL/hour.

Correct answer: C

Rationale: To infuse 100 mL in 45 minutes, the infusion rate should be set to 133 mL/hour (100 mL / 0.75 hours). This calculation is obtained by dividing the total volume to be infused by the total time for infusion (100 mL / 0.75 hours = 133 mL/hour). Therefore, choice C is the correct answer. Choices A, B, and D are incorrect because they do not accurately calculate the infusion rate required to deliver the medication within the specified time frame.

3. A client with a history of seizures is prescribed phenytoin. Which side effect should the nurse instruct the client to report?

• A. Drowsiness
• B. Gingival hyperplasia
• C. Weight gain
• D. Blurred vision

Correct answer: B

Rationale: The correct answer is B: Gingival hyperplasia. Phenytoin is known to cause gingival hyperplasia, which is an overgrowth of gum tissue. This side effect is important to report to the healthcare provider because it can lead to oral health problems. Choice A, drowsiness, is a common side effect of many antiepileptic drugs but is not specific to phenytoin. Choice C, weight gain, is not a typical side effect of phenytoin. Choice D, blurred vision, is not a common side effect of phenytoin; it is more commonly associated with other medications.

4. The nurse instructs the mother of a child with a ventricular septal defect that she can expect the child to become cyanotic when the child does what?

• A. Experiences an elevation in temperature.
• B. Sleeps on the left side.
• C. Cries vigorously.
• D. Eats.

Correct answer: C

Rationale: The correct answer is C: Cries vigorously. When the child cries vigorously, it increases the pressure in the right ventricle, allowing unoxygenated blood to enter the circulating volume, leading to cyanosis. This occurs due to the shunting of blood from the right side of the heart to the left side through the ventricular septal defect. Choices A, B, and D are incorrect because they do not directly impact the pressure in the right ventricle, which is crucial in causing cyanosis in this scenario.

5. Based on this strip, what is the correct interpretation of this rhythm?

• A. Atrial fibrillation.
• B. Premature atrial fibrillation.
• C. AV block.
• D. Ventricular tachycardia.

Correct answer: A

Rationale: The correct interpretation of the rhythm strip is atrial fibrillation. This arrhythmia is characterized by an irregular heartbeat and the absence of distinct P waves. Choice B, premature atrial fibrillation, is incorrect as there is no indication of premature beats in the strip. Choice C, AV block, is also incorrect as there is no evidence of conduction delays between the atria and ventricles. Choice D, ventricular tachycardia, is not supported by the absence of wide QRS complexes typically seen in this arrhythmia.

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