Nursing Elites

1. The nurse is caring for a 4-year-old child with a greenstick fracture. In explaining this type of fracture to the parents, the best response by the nurse should be that

• A. A child's bone is more flexible and can be bent 45 degrees before breaking
• B. Bones of children are more porous than adults and often have incomplete breaks
• C. Compression of porous bones produces a buckle or torus type break
• D. Bone fragments often remain attached by a periosteal hinge

Correct answer: B

Rationale: The correct answer is B. Greenstick fractures are common in children because their bones are softer and more porous than adult bones, leading to incomplete breaks when force is applied. Choice A is incorrect as greenstick fractures are not due to bone flexibility but rather the porous nature of children's bones. Choice C is incorrect as it describes a buckle or torus type break, which is not characteristic of a greenstick fracture. Choice D is incorrect as greenstick fractures do not involve bone fragments remaining attached by a periosteal hinge.

2. Which of the following is the most effective way to prevent the spread of communicable diseases in a community?

• A. Regular health check-ups
• B. Isolation of infected individuals
• C. Immunization programs
• D. Public health education

Correct answer: C

Rationale: Immunization programs are the most effective way to prevent the spread of communicable diseases. Vaccinations help build immunity against specific diseases, reducing the likelihood of an outbreak. Regular health check-ups (Choice A) are important for individual health but do not directly prevent the spread of diseases on a community level. Isolation of infected individuals (Choice B) is a containment measure rather than prevention for the entire community. Public health education (Choice D) is valuable in raising awareness but may not be as effective as immunization programs in directly preventing the spread of communicable diseases.

3. The family presents several problems. Which of the following criteria is considered in determining the priority health problem?

• A. expected consequence of the problem
• B. cooperation and support of the family
• C. involvement of the family members in the problem
• D. modifiability of the problem

Correct answer: D

Rationale: When determining the priority health problem within a family, one key criterion to consider is the modifiability of the problem. This means assessing whether the health issue can be changed or improved through interventions. Choices A, B, and C are not directly related to the priority of the health problem within the family. The expected consequence of the problem, cooperation and support of the family, and involvement of family members are important factors but do not specifically address the priority of the health issue based on modifiability.

4. While performing an initial assessment on a newborn following a breech delivery, the nurse suspects hip dislocation. Which of the following is most suggestive of the abnormality?

• A. Flexion of lower extremities
• B. Negative Ortolani response
• C. Lengthened leg of affected side
• D. Irregular hip symmetry

Correct answer: D

Rationale: Irregular hip symmetry, such as asymmetry in the gluteal folds, is a common sign of hip dislocation in newborns. This finding indicates a potential abnormality in hip development and requires further evaluation and possible treatment. Choices A, B, and C are incorrect. Flexion of lower extremities is a normal newborn reflex, the Ortolani response is used to detect hip dysplasia rather than hip dislocation, and a lengthened leg of the affected side is not typically associated with hip dislocation in newborns.

5. In 1996, there were 15 cases of Acute Respiratory Infection (ARI) in Barangay B, while Barangay C had 20 cases. The total number of children who have ARI is:

• A. higher in Barangay C than in Barangay B
• B. not comparable in Barangay B and C
• C. higher in Barangay B than in Barangay C
• D. data given is insufficient

Correct answer: A

Rationale: The correct answer is A: 'higher in Barangay C than in Barangay B.' This is because Barangay C had more cases of ARI (20) compared to Barangay B (15). Therefore, the total number of children who have ARI is higher in Barangay C. Choices B and C are incorrect because the data clearly shows that Barangay C had more cases than Barangay B. Choice D is also incorrect as there is sufficient data provided to compare the number of ARI cases between the two barangays.

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