the health care provider is treating a child with meningitis with a course of antibiotic therapy when should the nurse expect the child to be out of i
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Nursing Elites

HESI LPN

HESI Test Bank Medical Surgical Nursing

1. The health care provider is treating a child with meningitis with a course of antibiotic therapy. When should the nurse expect the child to be out of isolation?

Correct answer: C

Rationale: The correct answer is C because a child with bacterial meningitis should be isolated for at least 24 hours until antibiotic therapy has been initiated. This period allows the antibiotics to start working against the infection, reducing the risk of spreading it to others. Choice A is incorrect because isolation is not solely based on completing the course of antibiotics; the initiation is crucial. Choice B is incorrect as waiting for a negative CNS culture may take longer and delay necessary precautions. Choice D is incorrect as symptom resolution does not guarantee the eradication of the infection and may still pose a risk of transmission.

2. A young adult male is admitted to the intensive care unit with multiple rib fractures and severe pulmonary contusions after falling 20 feet from a rooftop. The Chest X-ray suggests acute Respiratory distress Syndrome. Which assessment finding warrants immediate intervention by the Nurse?

Correct answer: C

Rationale: In a patient with multiple rib fractures, severe pulmonary contusions, and possible acute Respiratory Distress Syndrome (ARDS), tachypnea (rapid breathing) with dyspnea (shortness of breath) is a critical sign of respiratory distress that warrants immediate intervention by the nurse. Tachypnea and dyspnea indicate inadequate oxygenation and ventilation, which can lead to respiratory failure if not addressed promptly. The other options, such as apical pulse rate, core body temperature, and bruises over the chest area, are important assessments but do not directly indicate the immediate need for intervention in a patient with respiratory distress.

3. Based on this strip, what is the correct interpretation of this rhythm?

Correct answer: A

Rationale: The correct interpretation of the rhythm strip is atrial fibrillation. This arrhythmia is characterized by an irregular heartbeat and the absence of distinct P waves. Choice B, premature atrial fibrillation, is incorrect as there is no indication of premature beats in the strip. Choice C, AV block, is also incorrect as there is no evidence of conduction delays between the atria and ventricles. Choice D, ventricular tachycardia, is not supported by the absence of wide QRS complexes typically seen in this arrhythmia.

4. A client with Addison's disease started taking hydrocortisone in a divided daily dose last week. It is most important for the nurse to monitor which serum laboratory value?

Correct answer: B

Rationale: The correct answer is B: Glucose. Hydrocortisone can lead to increased blood glucose levels, so monitoring glucose is crucial to assess for hyperglycemia, a common side effect of corticosteroid therapy. Monitoring osmolarity (choice A) is not typically indicated in this scenario. Albumin (choice C) and platelets (choice D) are not directly affected by hydrocortisone therapy and are not the primary focus of monitoring in this case.

5. A client with type 1 diabetes mellitus is experiencing nausea and vomiting. What is the most important instruction the nurse should provide?

Correct answer: D

Rationale: The correct answer is to instruct the client to check blood glucose levels frequently. During illness, such as nausea and vomiting, managing blood glucose levels is crucial in clients with type 1 diabetes mellitus. Monitoring blood glucose levels frequently helps in adjusting insulin doses appropriately, preventing complications like hyperglycemia or hypoglycemia. Choice A is incorrect because stopping insulin abruptly can lead to serious complications. Choice B is important but not the most critical in this scenario. Choice C is incorrect as high-carbohydrate foods may further affect blood glucose levels negatively.

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