Nursing Elites

1. A woman at 26 weeks of gestation is being assessed to determine whether she is experiencing preterm labor. Which finding indicates that preterm labor is occurring?

• A. Estriol is not found in maternal saliva.
• B. Irregular, mild uterine contractions occur every 12 to 15 minutes.
• C. Fetal fibronectin is present in vaginal secretions.
• D. The cervix is effacing and dilated to 2 cm.

Correct answer: D

Rationale: The correct answer is D. Cervical changes such as effacement and dilation to 2 cm are strong indicators of imminent preterm labor. These changes, combined with regular contractions, can signify labor at any gestation. Estriol can be detected in maternal plasma as early as 9 weeks of gestation. Levels of salivary estriol have been linked to preterm birth. Irregular, mild contractions occurring every 12 to 15 minutes without cervical change are generally not concerning. While the presence of fetal fibronectin in vaginal secretions between 24 and 36 weeks of gestation may predict preterm labor, its predictive value is limited (20%-40%). Therefore, cervical changes provide more reliable information regarding the risk of preterm labor.

2. A newborn assessment reveals spina bifida occulta. Which maternal factor should the nurse identify as having the greatest impact on the development of this newborn complication?

• A. Tobacco use.
• B. Folic acid deficiency.
• C. Short interval between pregnancies.
• D. Preeclampsia.

Correct answer: B

Rationale: Folic acid deficiency during pregnancy is strongly associated with neural tube defects like spina bifida occulta. Adequate folic acid intake before and during early pregnancy significantly reduces the risk of such complications. Tobacco use (Choice A) is linked to other adverse outcomes but not specifically spina bifida occulta. Short intervals between pregnancies (Choice C) can increase the risk of preterm birth and low birth weight but are not directly linked to spina bifida occulta. Preeclampsia (Choice D) is a hypertensive disorder that poses risks to both the mother and baby but is not the primary factor contributing to spina bifida occulta development.

3. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

4. A nurse is caring for an infant who has signs of neonatal abstinence syndrome. Which of the following actions should the nurse take?

• A. Provide a calm environment
• B. Monitor blood glucose levels every hour
• C. Initiate seizure precautions
• D. Place the infant on their back with legs extended

Correct answer: C

Rationale: Initiating seizure precautions is crucial when caring for an infant with neonatal abstinence syndrome due to the increased risk of seizures. Providing a calm environment (Choice A) is important to reduce stimulation as these infants may be irritable. Monitoring blood glucose levels (Choice B) is not typically a priority in neonatal abstinence syndrome unless specific signs or symptoms suggest the need for this assessment. Placing the infant on their back with legs extended (Choice D) does not directly address the potential complications associated with neonatal abstinence syndrome, such as seizures.

5. A nurse on the labor and delivery unit is assessing four clients. Which of the following clients is a candidate for an induction of labor with misoprostol?

• A. A client who has active genital herpes
• B. A client who has gestational diabetes mellitus
• C. A client who has a previous uterine incision
• D. A client who has placenta previa

Correct answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.

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