Nursing Elites

1. What nursing action should the nurse implement for a 3-hour-old male infant who presents with cyanotic hands and feet, an axillary temperature of 96.5°F (35.8°C), a respiratory rate of 40 breaths per minute, and a heart rate of 165 beats per minute?

• A. Administer oxygen by mouth at 2L/min
• B. Gradually warm the infant under a radiant heat source
• C. Notify the pediatrician of the infant's vital signs
• D. Perform a heel-stick to maintain blood glucose levels

Correct answer: B

Rationale: The correct nursing action is to gradually warm the infant under a radiant heat source. The infant is presenting with signs of cold stress, indicated by cyanotic extremities and a low body temperature. Gradual warming is crucial to stabilize the infant's temperature and prevent further complications. Administering oxygen, notifying the pediatrician, or performing a heel-stick are not the priority actions in this scenario and may not address the immediate need to raise the infant's body temperature.

2. A multiparous client at 36 hours postpartum reports increased bleeding and cramping. On examination, the nurse finds the uterine fundus 2 centimeters above the umbilicus. Which action should the nurse take first?

• A. Increase the intravenous fluid to 150 ml/hr.
• B. Call the healthcare provider.
• C. Encourage the client to void.
• D. Administer ibuprofen 800 milligrams by mouth.

Correct answer: C

Rationale: Encouraging the client to void is the priority action in this scenario. A distended bladder can prevent the uterus from contracting properly, leading to increased bleeding and a high uterine fundus. By encouraging the client to void, the nurse can help the uterus contract effectively, reducing bleeding. Increasing intravenous fluids or administering ibuprofen would not address the immediate concern of a distended bladder affecting uterine contraction. While it may be necessary to involve the healthcare provider, addressing the bladder distention promptly is crucial to prevent further complications.

3. A woman gave birth to a 7-pound, 6-ounce infant girl 1 hour ago. The birth was vaginal and the estimated blood loss (EBL) was 1500 ml. When evaluating the woman’s vital signs, which finding would be of greatest concern to the nurse?

• A. Temperature 37.9°C, heart rate 120 beats per minute (bpm), respirations 20 breaths per minute, and blood pressure 90/50 mm Hg.
• B. Temperature 37.4°C, heart rate 88 bpm, respirations 36 breaths per minute, and blood pressure 126/68 mm Hg.
• C. Temperature 38°C, heart rate 80 bpm, respirations 16 breaths per minute, and blood pressure 110/80 mm Hg.
• D. Temperature 36.8°C, heart rate 60 bpm, respirations 18 breaths per minute, and blood pressure 140/90 mm Hg.

Correct answer: A

Rationale: An estimated blood loss (EBL) of 1500 ml following a vaginal birth is significant and can lead to hypovolemia. The vital signs provided in option A (Temperature 37.9°C, heart rate 120 bpm, respirations 20 breaths per minute, and blood pressure 90/50 mm Hg) indicate tachycardia and hypotension, which are concerning signs of hypovolemia due to excessive blood loss. Tachycardia is the body's compensatory mechanism to maintain cardiac output in response to decreased blood volume, and hypotension indicates inadequate perfusion. Options B, C, and D do not exhibit the same level of concern for hypovolemia. Option B shows tachypnea, which can be a result of pain or anxiety postpartum. Option C and D have vital signs within normal limits, which are not indicative of the body's response to significant blood loss.

4. What causes sickle-cell anemia?

• A. A chromosomal abnormality.
• B. A single segment found only on the Y chromosome.
• C. A recessive gene.
• D. A decrease in estrogen levels.

Correct answer: C

Rationale: Sickle-cell anemia is a genetic disorder caused by inheriting two copies of a recessive gene, one from each parent. The correct answer is C. Choice A is incorrect because sickle-cell anemia is not primarily caused by a chromosomal abnormality. Choice B is incorrect as the condition is not linked to a single segment found only on the Y chromosome. Choice D is unrelated as it mentions a decrease in estrogen levels, which is not a cause of sickle-cell anemia.

5. Dizygotic (DZ) twins share _________ percent of their genes.

• A. 100
• B. 75
• C. 50
• D. 25

Correct answer: C

Rationale: Dizygotic (DZ) twins share approximately 50% of their genes. This is because dizygotic twins, also known as fraternal twins, originate from two separate fertilized eggs and share similar genetic similarity to regular siblings. Choice A (100%) is incorrect because if twins shared 100% of their genes, they would be identical twins (monozygotic). Choice B (75%) is incorrect as it is not the typical genetic similarity seen in dizygotic twins. Choice D (25%) is incorrect as it represents a significantly lower genetic similarity than what is observed in dizygotic twins.

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