Nursing Elites

1. A patient who is being treated for dehydration is receiving 5% dextrose and 0.45% normal saline with 20 mEq/L potassium chloride at a rate of 125 mL/hour. The nurse assuming care for the patient reviews the patient’s serum electrolytes and notes a serum sodium level of 140 mEq/L and a serum potassium level of 3.6 mEq/L. The patient had a urine output of 250 mL during the last 12-hour shift. Which action will the nurse take?

• A. Contact the patient’s provider to discuss increasing the potassium chloride to 40 mEq/L.
• B. Continue the intravenous fluids as ordered and reassess the patient frequently.
• C. Notify the provider and discuss increasing the rate of fluids to 200 mL/hour.
• D. Stop the intravenous fluids and notify the provider of the assessment findings.

Correct answer: D

Rationale: The patient’s potassium level is within normal limits, but the decreased urine output indicates the patient should not receive additional IV potassium. Increasing potassium chloride to 40 mEq/L is not needed as the level is normal. Stopping the IV fluids is appropriate due to the decreased urine output, which suggests potential fluid overload. The nurse should notify the provider of the assessment findings for further management. Increasing the rate of fluids to 200 mL/hour is not recommended without addressing the decreased urine output first.

2. What is the most common cause of coronary artery disease?

• A. Atherosclerosis.
• B. Hyperlipidemia.
• C. Diabetes.
• D. Smoking.

Correct answer: A

Rationale: The correct answer is Atherosclerosis. It is the primary cause of coronary artery disease, as it involves the buildup of plaque in the arteries, restricting blood flow to the heart. Hyperlipidemia (choice B) contributes to atherosclerosis by increasing cholesterol levels in the blood but is not the direct cause of coronary artery disease. Diabetes (choice C) can accelerate atherosclerosis due to high blood sugar levels, but it is not the most common cause. Smoking (choice D) is a significant risk factor for developing coronary artery disease but is not the primary cause.

3. A client with polycystic kidney disease (PKD is being assessed by a nurse. Which assessment finding should prompt the nurse to immediately contact the healthcare provider?

• A. Flank pain
• B. Periorbital edema
• C. Bloody and cloudy urine
• D. Enlarged abdomen

Correct answer: B

Rationale: Periorbital edema would not typically be associated with polycystic kidney disease (PKD) and could indicate other underlying issues that require immediate attention. Flank pain and an enlarged abdomen are common findings in PKD due to kidney enlargement and displacement of other organs. Bloody or cloudy urine can result from cyst rupture or infection, which are expected in PKD. Therefore, periorbital edema is the most alarming finding in this scenario and warrants prompt notification of the healthcare provider.

4. After teaching a client with bacterial cystitis who is prescribed phenazopyridine (Pyridium), the nurse assesses the client’s understanding. Which statement made by the client indicates a correct understanding of the teaching?

• A. I will not take this drug with food or milk.
• B. If I suspect pregnancy, I will discontinue the drug.
• C. An orange color in my urine should not alarm me.
• D. I will consume two glasses of cranberry juice daily.

Correct answer: C

Rationale: The correct answer is C. Phenazopyridine commonly discolors urine to a deep reddish orange, which can be mistaken for blood. It is important for the client to understand that this color change is an expected side effect and should not be a cause for alarm. Additionally, the urine can stain clothing. There are no dietary restrictions or precautions related to food or milk intake while taking phenazopyridine. Stopping the medication if suspecting pregnancy is not necessary as phenazopyridine is safe to use during pregnancy. Drinking cranberry juice is not directly related to the use of phenazopyridine and is not a specific instruction given for managing bacterial cystitis.

5. The client admitted with peripheral vascular disease (PVD) asks the nurse why her legs hurt when she walks. The nurse bases a response on the knowledge that the main characteristic of PVD is:

• A. Decreased blood flow.
• B. Increased blood flow.
• C. Slow blood flow.
• D. Thrombus formation.

Correct answer: A

Rationale: The correct answer is A: 'Decreased blood flow.' In peripheral vascular disease (PVD), there is a narrowing or blockage of blood vessels, leading to reduced blood flow to the extremities. This decreased blood flow results in inadequate oxygen supply to the muscles, causing pain, especially during physical activity when oxygen demand increases. Choice B, 'Increased blood flow,' is incorrect because PVD is characterized by impaired blood circulation rather than increased flow. Choice C, 'Slow blood flow,' is not precise as PVD involves a more significant reduction in blood flow. Choice D, 'Thrombus formation,' is related to the formation of blood clots within vessels, which can be a complication of PVD but is not its main characteristic.

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